Java does not support opperator overloading, so the answer to your question is: none.

I'm not sure I fully understand the question. Operators and functions are not the same. However, many operators also have named alternatives implemented as functions, such that "add" is synonymous with the binary increment operator while "plus" is synonymous with the unary plus operator. However these are completely separate implementations that do the same thing such that the function implementation typically invokes the operator (with implicit inline expansion to factor away the unwanted function call). There is no way to determine the underlying function of an operator, nor the underlying operator of a function without having access to the implementation source code. Such implementation details cannot be accessed at compile time let alone runtime.

An Operator's first priority if they are involved in an accident with another vessel, is to report the accident. You should do this as soon as possible. This will aid you in getting help to you and the other parties.

The different types of operators are as follows: *Arithmatic operator *Relational operator *Logical operator *Assignment operator *Increment/Decrement operator *Conditional operator *Bitwise operator *Special operator

Yes, a string can contain operator symbols, eg:

const char *s= "+*-/";