12^2+2^2+1^2+1^2 = 144 + 4 + 1 + 1 = 150.
30
81 + 1 + 1 + 1
1+4+9=14
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
the two numbers are 8 and 4
30
33, 36, 39, 42
25= 5*5 = (3*3)+(4*4)
here are some 144 4 1 1 9 16 25 100 1 36 49 64
There is no particular characteristic that is common to such numbers other than they are positive integers greater than or equal to 4.
The numbers are 3, and 4.
If you have a data set, simply take the square root of the sum of the squares of the data points. Let's say you have three numbers a, b, and c. RSS = SQRT(a2 + b2 + c2).
i have two answers: 100+25+16+9=150 16+4+121+9=150
81 + 1 + 1 + 1
1+4+9=14
This could be the solution to the sum : 12 + 22 = 1 + 4 = 5
12+22+32+42+52+62 = 1+4+9+16+25+36= 91