23 volts across 470 ohms will dissipate about 1.1 watts.
Power equals voltage squared divided by resistance.
ohms is a measure of resistance(R) in a circuit. Watts is a measure of the power(P), in this case lets assume it is the power used by the resistive element (lamp, heater etc). Power(watts)=Current(Amps)x Current(amps) x Resistance(ohms) or Resistance (ohms)=Power(W)/(current x current)
97000ohms
Without specific information I cannot answer your question, however you can work it out. For a dc or single phase system you need to know 2 simple laws. P=V x I & V=I x R where: P = power in watts V = Voltage in Volts I = Current in Amps R=Resistance in Ohms we can therefore derive that since I=V/R and P=V x I then P=V x V/R or vsquared over R or in your case R = V(squared) / P = 12 x 12 / 30 = 144/30 = 4.8 ohms Now use the formula supplied with your voltage value, and you will know what the resistance is . See isn't math fun.
4 ohms
2600 ohms.
470.... apparently :P
250 watts approximatelyI assume you have a constant voltage supply. According to P=V^2/R => P*R=V^2, you have a 44.7 volt supply. If you change Resistance to 8 ohms, P=44.7^2/8 => P=250 watts.
The formula you are looking for is, R = Volts (squared)/Watts.
Though it is tempting to say the difference is 2 ohms (8 ohms minus 2 ohms equals 6 ohms), lets look at some things. The 6 ohms is 3/4ths the resistance of the 8 ohms. If the resistances are loads, the 6 ohm load will draw 1/3rd more current than the 8 ohm load. The 8 ohm load will draw 3/4ths as much as the 6 ohm load. Those are some differences between 6 ohms and 8 ohms.
Watts = Volts x Amps x Powerfactor Volts = Amps x Ohms Note: Power Factor is one for resistance loads and decreases toward zero for loads like motors. watts=VI=v*v/R=I*I*R volt=IR=square root of PR=P/I Ampere=V/R=P/V=square root of P/R ohms=V/I=V*V/P=P/I*I
It is 470.
Earthing of the negative terminal is a common practice and will not affect the potential across the resistors in the circuit. Calculating this is simple Ohm's Law. For a series circuit: R(total) = R1 + R2 + R3....... Rn In this case: Rt = 120 + 470 = 590 ohms Per ohms law E = I x R. We need to find the current flowing throught the circuit so: I = E/R = 12 / 590 = .0203 amps or 20.3 milliamps The potential across an individual resistor is calculated again by E = I x R So for R1 (120 ohms): E1 = I x R1 = .0203 x 120 = 2.44 V So for R2 (470 ohms): E2 = I x R2 = .0203 x 470 = 9.54 V For a check E = E1 + E2 = 2.44 + 9.54 = 11.98 The .02 difference is due to the use of significant figures.Another AnswerEarthing the negative terminal will have no affect on the potential DIFFERENCE across each resistor. 'Potential' exists at a single point. 'Potential difference' exists between two points.
81% of 470= 81% * 470= 0.81 * 470= 380.7
30% of 470= 30% * 470= 0.3 * 470= 141
Other than the integer 470, the simplest form is 470/1.Other than the integer 470, the simplest form is 470/1.Other than the integer 470, the simplest form is 470/1.Other than the integer 470, the simplest form is 470/1.
470
0.069444444444444444444444444444444444 ohms. P/E^2=R. P = power in watts. E = electricity in volts. R = resistance in ohms.