Whilst travelling downstream the boat travels at V + C mph where V is the speed of the boat in still water and C is the speed of the current.
Whilst travelling upstream the speed is V - C mph.
The downstream velocity = 24/2 = 12mph = V + C therefore C = 12 - V
Velocity (speed) = Distance ÷ Time : therefore Distance = Velocity x Time.
As the distance in either direction is the same then,
2(V+C) = 3(V-C)
2V + 2C = 3V - 3C
V = 5C : substituting for C as C = 12-V
V = 5(12 - V) = 60 - 5V
6V = 60 : V = 10 mph. Therefore, C = 12 - 10 = 2 mph
The speed of the boat in still water is 10 mph and the speed of the current is 2 mph.
The average speed downstream is 40 ÷ 4 = 10 mph. However, it would seem that insufficient information has been supplied to enable a satisfactory answer to this question to be provided.
To do this, you need to form equations using the information given. There are 2 variables here, the base speed of the rower with no current (x), and the speed of the current (y). Firstly, convert the distances and times given into average speeds. 20km/2 hours = 10km/h 4km/2 hours = 2km/h The actual speed = the base speed +- the current, depending on direction. So 10 = x + y 2 = x - y If we subtract these 2 equations to eliminate x, we get: 8 = 2y y = 4km/h
15 miles
What is my distance if i travel for 1.5 hours at 70 miles per hours?
If you travel at 60 mph, it would take 2 and a half hours. If you travel at 65 mph, it would take 2 hours and 18 minutes.
It is 5 miles per hour.
35 mph
35 mph
Velocity = Distance ÷ Time.The speed upstream = 300 ÷ 5 = 60kph.The speed downstream = 300 ÷ 2 = 150 kph.The speed upstream equals boat velocity(Vb) minus current velocity(Vc).The speed downstream equals boat velocity (Vb) pluscurrent velocity (Vc).Vb - Vc = 60Vb + Vc = 150 : Adding the two equations together gives :-2Vb = 210 : Vb = 105, therefore Vc = 45The rate of the boat in still water is 105 kph. The rate of the current is 45 kph.
Since the distance downstream (with the current) equals the distance upstream (against the current), and if we: Let B stand for the speed (rate in mph) of the boat in still water, and using the formula rate X time = distance, the equation will be: (B+7) x 3 = (B-7) x 5 3B + 21 = 5B - 35 56 = 2B B = 28 mph Traveling downstream, the current will cause the boat to go faster so the 7 mph current is added to the boat's still water speed. Traveling upsteam the current slows or decreases the boat's rate so the current's speed is subtracted from the boat's still water speed.
Boats speed = 24 miles per hour.Current speed = 4 miles per hour.
The average speed downstream is 40 ÷ 4 = 10 mph. However, it would seem that insufficient information has been supplied to enable a satisfactory answer to this question to be provided.
If 4 hours return seven then 6 hours has return in 4 hours and 2 more hours will no return within 4 hours.
About £95, but the cost could be cheaper if you have a railcard or travel at unsociable hours.
The speed of the boat is 36 km/h. Going upstream: 3h x 36km/h = 108 km, minus (6x3 =18 km) = 90 km Going downstream: 2h x 36km/h = 72 km, plus (6x2 =12 km) = 90 km
It takes approximate 1 hours 40 minutes travel time from Swift Current, Saskatchewan to Moose Jaw, Saskatchewan, a distance of 173.7 kilometers via the Trans Canada Highway.
Too much.. More than any other transport.. £250 return train fare to Edinburgh > 6.5 hours travelling..... £60 return + £65 Car parking from Stansted to Edinburgh > 3 hours or less! £100 to drive car there and back > 10 - 15 hours!