If the generator produces 240v at 25 amps, this amounts to 6000 watts, so if the losses are 900 watts, the total power generated must be 6900 watts. The efficiency is then 6000/6900 = 0.87, or 87 percent. You have not put in heat losses however, or are they included in 'mechanical? ****The previous answer above is incorrect. Read and understand the question first. The general rule of thumb when calculating power equations is to factor in power loss as an inclusive amount of the total power being generated. unless stated otherwise Therefore 240v at 25amps gives 6000watts power loss is 900watts The question says that the power the generator produces is 240v at 25amps which is not the useful power it delivers ( this is a very common mistake in learning and real life applications) and that is why we do not add power loss to the total power generated, rather we subtract power loss from the total power generated. Efficiency of the generator is actually the power the generator is delivering for useful work compared to the total power generated. In this case 6000 watts (Total power produced) - 900watts ( power loss) = 5100watts Therefore the geneator's efficiency is 5100/6000 x 100% = 85% For the last part of the previous answer, For a generator, mechanical movement is counter reacted by friction which produces heat and noise while resistance to electrical current flow and electomagnetic induction generate heat. Of course this is just a general description, it gets quite complicated in advanced level analysis where back e.m.f, magnetic resonance, physical construction (generator type) and purity of construction materials just to mension a few are involved. I'm only a simple physicist, but I feel the word 'produced' is ambiguous, and I took it to mean the same as 'delivered'. If I went out and bought a small generator, and the sales people said it was a 2 Kw generator, I would expect it to deliver 2 Kw, and not 85 percent of that figure. So I think you could take this either way. To use the word 'produced' is not ideal, better to use 'generated power' and 'output power'.
Efficiency is measured as the ratio of power output to power input. In this case the power input of the generator is 240V * 25A = 6000 VA however the stated losses are 900 W so the power output is 6000 - 900 = 5100W. Then the efficiency would be 5100/6000 = 0.85 or 85% efficient.
Yes.
The equation you are looking for is Amps = Watts/Volts. To change kW to watts, multiply kW x 1000.
240Volts in the USA.
The easiest way is with a transformer that gives the ratio of (277/240) times.
No
yes 240volts is 240 volts
Check the back of the charger, if it says "100-240volts" than yes.
1 d0nt kn0w but have fun
Pwer is volts times amperes. 120 volts times 10 amperes = 1.2 KW
Yes, the adaptor can take anything from 100 to 240 v.
If it is an incandescent lamp, then it will run on 240volts, but not at full wattage. If it is an HID type that has a ballast, no, it will not.