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32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;

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14y ago
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16 address lines can address 216 or 65536 different locations.

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13y ago

With 24 address lines, you can address 224 or 16,777,216 different memory locations.

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Q: A microprocessor has 24 parallel address lines How many memory locations can the processor address?
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Why segment is 64k in microprocessor?

Because the processor is a 16 bit processor, and 64k is what you can address with a 16 bit processor.


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the 8085 microprocessor is a 8-bit microprocessor and these are bidirectional but the address lines are unidirectional.these address lines are used to address the location of the instruction in memory .these data lines are used to transfer data between processor and peripheral devices. when the address of the instruction will be recognized by the address lines the data will be send to the processor therefore the 16 address lines are not act as a data lines in 8085


How many memory location can be address by microprocessor with 14 address line?

You can address 214 or 16384 different locations with 14 address lines.


How many locations can be addressed by a microprocessor with 14 address line?

2^14 memory locations. In general for n-bit address bus, its 2^n


How many memory locations can be addressed by a microprocessor with 14 address lines?

2^14 memory locations. In general for n-bit address bus, its 2^n


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How many memory location can be addressed by microprocessor 8085?

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What is the What is the maximum memory address space that the processor can access directly if it is connected to a 8 bit memory considering a hypothetical microprocessor generating a 8 bit address?

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What is the need of Instruction PointerIP in 8086 microprocessor?

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