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A program to find sum of digits repeatedly until a single digit is obtained?
Wiki User
∙ 13y ago
#include<stdio.h>
#include<conio.h>
main()
{
int n,s=0,sum=0,i,d;
printf("enter the number");
scanf("%d",&n);
while(n>0)
{
d=n%10;
s=s+d;
n=n/10;
}
while(s>0)
{
i=s%10;
sum=sum+i;
s=s/10;
}
printf("%d",sum);
getch();
}
Wiki User
∙ 13y ago
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Write a pseudo code to find the sum of digits of a given number reducing them to a single digit?
5
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We only include the headers we actually use. It would be impractical to include every single header in every single program.
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by using decimals
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If necessary.
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Digits.
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1234679
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9
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The ones column are in single digits and if there are none then the 0 digit is used.
Is 24815 divisible of 9?
No. To check for divisibility by 9 add the digits of the number and if the sum is divisible by 9 then the original number is also divisible by 9, otherwise it is not. For 24815: 2 + 4 + 8 + 1 + 5 = 20 which is not divisible by 9, so 24815 is not divisible by 9. Note that the test can be applied to the sum: repeatedly summing the digits of the sum of the digits until a single digit remains means the original number is divisible by 9 only if this single digit is 9, otherwise it is not (instead it gives you the remainder when the original number is divided by 9). This single digit is known as the digital root of the number.
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A single program is also known as uni programming. Uni programming only allows on program to be present in the memory at a time. Single program
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Digits
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A digit is a single number. For example: 0 to 9 are single digits.
What is in digits?
There is nothing "in" digits. Digits are single characters representing the ten integers from 0 to 9 (inclusive).
