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Can you reduce amperage by using thicker wire with a constant voltage?
The amperage flowing through a wire is directly related to the load placed on the circuit, and has nothing to do with wire size, except that a larger wire will carry more amperage. Increasing wire size will not lower amperage but will allow the circuit to carry more amperage if the breaker is also increased in size.
No. Ohm's law tells us that V = IR. For a given load, R is constant, and thus the only way to reduce current is to increase voltage.
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Amperage, or current, is a measure of the amount of electrons moving in a circuit. Voltage is a measure of how much force those electrons are under. In a circuit…, say a light and switch in your home when the light is on there there is a voltage across the filament of the bulb that is pushing amperage through the circuit. When the switch is off there is voltage across the switch but there is no current flowing because it is "blocked" by the switch. An analogy that normally helps to illustrate the difference between voltage and amperage: you have a garden hose, the nozzle is closed. You've got pressure but no flow-voltage but no current (amperage). Open the nozzle and the pressure in the hose causes the water to flow - turn on the light and the voltage causes the current to flow (amperage) Answer (in understandable terms) Voltage is how much electricity there is. Amperage is how fast that electricity is moving (if at all). There are other things involved in electricity, electrical currents, etc., but this question is about amperage ("amps") and voltage ("volts"). Here's a good analogy. Imagine you have a bucket and a regular watering hose. The hose is connected to a spigot, or spout (which is the thing where you turn the water on and off by twisting the little handle), but the water is 'turned off' at the moment. And although it is 'off,' it could easily be turned back 'on' by twisting the handle and allowing the water to flow out. Also, the more you twist, the more water comes out. Don't worry -- this will all tie together. :) If there was no spigot then water would be flowing out all over the place, all the time (until there was no more water), because there'd be no resistance to block it from flowing. That being said, when you're done using a hose and you go to 'shut the water off' (by tightening the handle on the spigot), what you're actually doing is forcing the water to stop flowing because when the handle gets tighter, on the other end of the handle is a little piece of metal that gets forced into the pathway of the water-flow, which in turn restricts how much water can come out; if you tighten the handle all the way, the little metal thing will be completely blocking any water from flowing out -- when the water stops coming out, you've officially 'shut the water off.' Likewise, if you want to fill your bucket up with water, you'll need to turn the water on, which you accomplish by twisting the handle in the other direction. This, in turn, moves the metal thing away from blocking the water, resulting in a flow (of water) into the hose. Now, you can use the hose to point the water so that it flows into the bucket. And, the more you loosen the handle on the spigot, the more water comes out at once. This is basically the how amperage & voltage work. Like it says above, voltage is how much -- amperage is how fast. And again, if there was no 'spigot-metal-thingy-blocker' to get in the way, water would be flowing out everywhere; and if you shut the water off, using the 'thingy-blocker,' water stops flowing. Either way, regardless of whether the water is on or off, 'how much' water there is sitting on the other side of the spigot doesn't change (unless you forget to pay the water bill). The same is true for voltage -- the number of volts doesn't change. What does change is the "rate of flow" -- aka "how fast it's flowing." Amperage can be defined as exactly that: the rate of flow (or current). You can have all the water ('voltage') in the world but if it's not flowing (because the spigot is shut off), and therefore the rate of flow ('amperage') is 'zero,' you'll NEVER fill your bucket (Try it! Put a hose in an empty bucket, and don't turn the water on -- I'll bet you'll find that the bucket stays pretty dry). :) Ultimately, to sum up, you can think of it like this: Voltage is useless without amperage. If it's just 'sitting there' then it's probably not doing much of anything that would benefit you. Amperage 'doesn't exist' if there's no voltage. How can there be any rate of flow if there's nothing flowing in the first place? Now (if you haven't fallen asleep already), maybe (hopefully) you can figure out / understand why & how it is that a smoke detector uses a 9-volt battery, while a car uses a 12-volt battery (not much difference), and-- well, you get the point. Answer think of it this way... There is a water source like a lake, the lake flows into a river, and there is a dam at some portion of the river and then there is at the end of the line the ocean. The lake is the source or (Service Connection 120/240) The river is the current (amperage) the dam is the (switch), and the boulders, ravines, and sandbars are restrictions of the flow of water which is (Ohms -Resistance)the ocean is then the end of the line. another answer for the mechanically minded this is not exactly a true representation and can be construed as the wrong forces in motion but for a releationship diagram it depicts the hierarchy and extent each principal has on each other. in a internal combustion engined car voltage is like horsepower in a car this is all the energy available to do work amperage is the accelerator... how much power that can flow at a given moment gearbox is like a transformer.
Can you reduce amperage by using thicker wire or will this only avoid energy loss overheating and melting?
Normal household current is carried over a 10/2 wire. This is good to carry up to 20 amps. The more amps you wish to carry the larger the wire required. The smaller the numbe…r the larger the wire. 8/2 is larger than 12/2. outside of the "standard room temperature" of the resistance of a given size of wire there is something called "heating losses" in any given size of wire ... simply put, the resistance of a given length of wire increases as it's temperature increases... drawing current thru a wire causes a certain degree (no pun intended) of heating, thus raising the resistance and lowering the voltage/current available to the load... normally (with the proper size of wire for the length of run) these effects (rt resistance/heating losses) are minimal. another name for the heating losses is "IRsquared loss" .
Answer Voltage indicates the potential difference between two points. Ampere is the unit for current, indicating the magnitude of current. Voltage is due to …which the current flows...and ampere is unit used for that current Voltage(V) and Ampere(A) can be related as follows R=V/I here I is the current(A) and v=voltage and R is termed as resistance Resistance is actually a opposing factor for the flow of current email@example.com
voltage is pressure amperage is number of elections per sec/
If you are referring to a simple circuit, you could add resistance throughout it. Increased resistance means decreased current flow yet the same voltage.
Yes. The current will vary depending on the varied resistive load placed on a fixed voltage. Lower the resistance, and current will increase.
Is there a chart available that will show the wire size amperage and voltage and distances that will be needed to safely wire a circuit?
You didn't specify the voltage that you are using but here is a simple easy to read chart that may meet your needs: http://www.fennelfamily.com/gti-vr6/electrical/cabl…e-length.html You can google "wire gauge distance" for more charts. Be careful and good luck!
Voltage is the "pressure" of electricity, whereas amperage (current) is the "flow" of electricity. Voltage can be present without amperage (at a switch in the off position), b…ut amperage can not exist without voltage. Once you flip the switch and the light turns on, you now have amperage. Voltage is measure in volts (E). Current is measured in amperes (I). Related terms would be Power and Resistance. Power (P) is measured in watts. Resistance is measured in ohms (R). P = I x E E = I x R
As what i know, 30-50 Ampere per cathodes
As long as you don't exceed the current rating of the cable.
Amperage is the measure of electrical current, which is the measure of the electron flow through something (like a wire). The more electrons that flow through the wire, the h…igher the amperage. Current is understood as moving from higher voltage to lower voltage but since electrons are negatively charged, they actually flow in the opposite direction. Voltage is a measure of electrical potential between two items. The electrical potential can be looked at as the difference in the electrical charge between two items. The item with more negatively charged electrons has a lower voltage.
True or false if the voltage and resistance of a circuit stay constant the amperage can never change?
The equation for the three values in the question will give the definite answer. Amperage (I) is equal to the voltage (E) divided by the resistance (R). I=… E / R So as you can see the answer is True. Example: 10 Volts and 50 Ohms in a circuit will have a current of .2 Amperes flowing through it. 10 / 50 = .2 You can also rearrange the equation to find the other two: E= R * E R= E / I
Transformers are used to increase the voltage and reduce the current in overhead power lines but wont increasing the voltage subsequently increase the current as resistance is a constant?
You're assuming that the line is dead shorted. In that case, assuming zero source impedance, current would increase as well. In reality, source impedance often limits the very… high voltage short circuit current to less than the lower voltage. Think of it this way: I have a 120 volt, 5000 watt totally resistive load (no motors). At 120 volts, I am pulling 41.67Amps. Say the power plant supplying this load is 100 miles away, and the overhead power line (regardless of voltage level) has .01 ohms/mile resistance (total of 1 ohm resistance). If the power company tries to deliver power at 120 volts, instead of the 5000 watts I want, I will get 5000 watts, but the power company will have to generate (5000 + 1 * 41.67^2) = 6736 watts*. If instead the power company steps the voltage up to say 13.8kV right outside my house (as close to the load as possible), total current at 13.8kV will be 362mA, so total power loss in transmission is .131watts (as opposed to 1736 at 120 volts). From the 120 volt perspective, my 5000 watt load "looks like" 2.88 ohms, since P = V*I = V^2/R. If we are looking at my house through a 13.8kV/120v transformer, the transformer has a turns ratio of 13800/120 = 115, thus increases voltage by 115 times, and decreases current by 115 times (from lowside to highside). Thus from the 13.8kV perspective, my 5000 watt load "looks like": P = V^2/R = (120 * turns_ratio)^2/R = (120*115)^2/R = 13800^2/R R = 38,088 ohms. The transformer changes voltage and current inversely to each other; this results in a change in apparent impedance relative to the highside and lowside of the transformer. *This is assuming the power company is delivering voltage at 120 volts through the line, and uses some sort of reactive power to compensate for the voltage drop through the line. This is often done by installing capacitor banks, or having generators closer to the load produce reactive power. The wasted transmission losses plus the cost of this extra equipment would result in higher power costs being passed on to customers.
Ampers are the ones that kill. But if there is too little voltage the electricity will not get through your body. On the other hand if theres 100000volts. and like 0.0000001 a…mps. You will also die because your heart cant take the shock.
Ohm's Law is Voltage = Resistance x Current So if you hold resistance constant, an increase in Voltage increases current by a proportional amount and vice versa if you decreas…e voltage.
To answer this question the resistance of the load is needed. I = E/R.
What is CLT wire and why can it with stand higher amperages and voltages than other wires types of the same size?
I researched CLT wire and found 2 possibilities. One is a heat trace cable and the other is a current limiting FLAT 2 conductor cable for 12 and 24 volt systems. I can only gu…ess since your question involves "higher amperages" than other conductors that you are referring to the heat trace cable. In either case, however, I believe the answer is the same. Different types of insulation can handle different amounts of current. The ampacity of a conductor is limited mostly by its insulation. This is to say that any BARE conductor in a certain application can carry more amps than it can with insulation. In most any case, the insulation melts and burns at temperatures below when the conductor itself melts. Glass or porcelain may be exceptions, as in fuses, but these insulators are not in contact with the conductors they protect. The voltage limit of a conductor is the maximum safe voltage an insulation can handle before the voltage breaches it, regardless of how many amps are flowing. The most common conductors in use today are rated for 600 volts. This rating means that applying more than 600 volts on the conductor could result in the voltage breaching (coming through) the insulation and allowing current to flow to any nearby conducting material, such as conduit or a panel enclosure. In other words it may be as if there is no insulation at all. This rating is mostly determined by insulation thickness, though material also plays a role.