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Choose the most likely products from the reaction of Al2s3 plus Ba?
Wiki User
∙ 9y ago
Barium is a more active metal than aluminium. In fact, the lower elements in the activity series gains electrons from the higher elements, which are also called as displacement reactions. The final products of this reaction would be barium sulfide and aluminium metal.
Wiki User
∙ 11y ago
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Is aluminum and sulfur likely to form a compound?
Yes, called aluminum sulfide, Al2S3
What represents a correct chemical equation describing the reaction between aluminum metal and sulfur?
2Al + 3S -> Al2S3
Chemical formula for aluminum sulfide?
S2Ur5 NO this is wrong! There isn't even an element that is Ur wow! The answer is Al2S3
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
Is Al2S3 soluble?
Yes
What is the chemical equation describing the reaction between aluminum and sulfur?
2Al + 3S ==> Al2S3
Is aluminum and sulfur likely to form a compound?
Yes, called aluminum sulfide, Al2S3
What represents a correct chemical equation describing the reaction between aluminum metal and sulfur?
2Al + 3S -> Al2S3
Represents a correct chemical equation describing the reaction between aluminum metal and sulfur.?
2Al + 3S -> Al2S3
How do you balance Al plus S equals Al2S3?
2Al+3S--->Al2S3
What is correct chemical equation describing the reaction between aluminum metal and sulfur?
The chemical equation is:2 Al + 3 S = Al2S3
How many moles of Al2S3 are in 100 g of Al2S3?
100/150.158 is 0.666 moles
Can solid sodium chloride react with aqueous aluminium sulfide in a reaction that requires heat?
Aluminium sulfide is not soluble in water; Al2S3 is easily hydrolyzed.
What is the number of moles in 510 g of Al2S3?
510 g Al2S3 is equal to 3,396 moles.
Chemical formula for aluminum sulfide?
S2Ur5 NO this is wrong! There isn't even an element that is Ur wow! The answer is Al2S3
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
Is Al2S3 soluble?
Yes
