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Consider a logical address space with 4 pages of 1024 bytes per pageeach mapped onto a physical memory of 64 frames. how many bits are there in logical address?
Wiki User
∙ 15y ago
4 pages -> 2^2 bits
1024 bytes -> 2^10 bits
64 frames -> 2^6 bits
Therefore:
Logical memory = 2+10=12 bits
Physical memory = 10 +6 =16 bits
Wiki User
∙ 15y ago
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