1st you must find the molar mass of CaBr2.
Ca 40.08g * (number of moles in the compound) 1
Br 79.90g * 2
This give you the amount (g) in 1 mole of CaBr2.
Multiply by 14 and you get the answer.
The answer is 14 moles.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
Step 1: balanced equation for the synthesis of ammonia:N2 + 3H2 --> 2NH3Step 2: convert 10g H2 to moles:H2=2 g/mol; 10g = 5 moles of hydrogen.Step 3: use molar ratios (coefficients) in balanced equation to determine moles of product:3/2=5/x; solve for x to get 3.3 moles of ammonia (product).Step 4: use relationship between moles and grams to get grams of product:NH3=14+1+1+1=17 g/mol. Given 3.3 moles, 17(3.3)=56.1 grams NH3.
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
molar weight of N = 14 grams/mole 35.7 grams/14 grams/mole = 2.55 moles
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
The answer is 14 moles.
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
14 grams per micron
atomic waight of hydrogen = 1.0079 weight of one mole of hydrogen = its atomic mass in grams(just like all elements). therefore 454g/1.0079g = 450.4 moles of hydrogen.
mol = mass/ Mr Mr = 14 + 3 = 17 mol = 1200/17 moles = 70.59
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
multiply it by 564 and divide it by 34
Step 1: balanced equation for the synthesis of ammonia:N2 + 3H2 --> 2NH3Step 2: convert 10g H2 to moles:H2=2 g/mol; 10g = 5 moles of hydrogen.Step 3: use molar ratios (coefficients) in balanced equation to determine moles of product:3/2=5/x; solve for x to get 3.3 moles of ammonia (product).Step 4: use relationship between moles and grams to get grams of product:NH3=14+1+1+1=17 g/mol. Given 3.3 moles, 17(3.3)=56.1 grams NH3.
Molar weight of C6H14 - 6*12 + 14* 1 = 86g Therefore 2.25 moles = 86 * 2.25 = 193.5g