I is a straight line originating from a certain y=intercept and then intercept x-axis and ends on the same initial value of velocity but this time it is negative.
When the ball leaves your hand (that is when you throw it up) it already has some velocity, this is where the line intercepts y-axis at whatever the value of velocity is. As it goes up till its height the velocity is zero here it cuts the x-axis at whatever time the ball is at it's peak. Then when the ball comes down the velocity is opposite to the previous one thus it will be negative bow and moves down the x-axis and ends where the initial till the initial value of velocity because of law of conservation of energy.
The velocity of the ball decreases from the acceleration of gravity over time as quantified in the relationship
v(t) = v(0) - g(t); where v is the velocity at some time t, v(0) is the initial velocity of the ball thrown into the air, and g is the acceleration of gravity, 9.8 m/s^2 (32.2 ft/s^2).
If the velocity begins at v it steadily decreases to zero. It continues to decrease until (neglecting air resistance) it reaches -v and hits the ground.
The acceleration is constant at -9.81 m/s/s.
Their accelerations are the same. Regardless of an object's initial velocity, (or the direction of that velocity), its downward velocity grows by 9.8 meters (32.2 feet) per second, every second after it is released.
The velocity is 0 at its maximum height because for that second it is not moving in any direction. It's constantly accelerating downwards and the acceleration is 9.8 m/s squared.
Because it's responding freely to the Earth's gravitational field the entire time.
The change in speed each second is 9.8 meters per second (32.2 feet per second) greater towards down, beginning the instant it leaves your hand, i.e. on the way up as well as down.
9.8 meters per seconds squared in the downward direction.
It comes back downward! :) enjoi!
zero
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
Yes. Acceleration is independent of speed. A perfect example of an object with zero speed but nonzero acceleration is an object at the apex of being thrown upward. The entire time it is in the air it is accelerating downward. At its maximum height its speed is zero.
9.8 meters per seconds squared in the downward direction.
If it is gravitational acceleration then it it is positive in downward and negative in upward direction..if it is not gravitational acceleration then it is depending upon the value of acceleration.
It comes back downward! :) enjoi!
The thrown ball will (usually) have the highest velocity as the acceleration (resultant of force) used to throw it exceeds that of the other two balls. The ball thrown upward will have a higher downward velocity than the dropped ball even though their accelerations (due to gravity) are the same, as it has more time to travel downward. Although, If the ball thrown upward is thrown high enough, it may even travel faster than the ball thrown downward if the downward throw's force is not enough to beat the ball's terminal velocity (quite a bit of height would be required though).
zero
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
No, the acceleration at the highest point is never 0.
Yes. Acceleration is independent of speed. A perfect example of an object with zero speed but nonzero acceleration is an object at the apex of being thrown upward. The entire time it is in the air it is accelerating downward. At its maximum height its speed is zero.
The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward
upword acceleration is -9.8 and downword is 9.8m/s^2
From the time the object leaves your hand, its acceleration doesn't change at all ... it remains constant at 9.8 meters (32.2 feet) per second2 downward. Well, we have to admit that the acceleration does change to zero once the object hits the ground.
Yes. There can be an instant during a period of acceleration when speed is zero. We can think of two examples right away: 1). Drop an object from your hand. As soon as you release it, downward acceleration begins immediately, but speed is zero. 2). Toss an object (like a baseball or a stone) straight up. Downward acceleration due to gravity begins immediately. At first, its effect is to reduce the upward speed. As soon as the upward speed is all gone, downward speed begins. Acceleration is constant throughout, but at the instant when upward speed becomes downward speed, the speed is zero.