No it is not fully obeying the octet rule.
Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet.
Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
No, Beryllium is an exception to the octet rule.
There is no chemical by the formula BF6.
BF3 exists, but it doesn't obey octet rule
No, Beryllium is an exception to the octet rule.
No
yes PCl3 obey octet rule there are 5 electrons in the valence shell of phosphorous it need 3 electron to complete its octet so it form bond with 3 chlorine after bond formation there are 8 electron in its octet it obey octet rule
because it does
The oxygen atoms in the ion do obey the octet rule. The phosphorus atom has more than eight electrons in its valence shell. It is because of the existence of vacant 3d orbitals.
Yes. Both O-F bonds are single covalent, so all three atoms can claim 8 electrons.
When sodium loses its single valence electron, it achieves the noble gas configuration of neon, which is an octet.
No chlorine oxides will obey the octet rule.
F2ccf2
Hydrogen does not obey the octet rule. Boron does not always obey the octet rule and in fact forms Lewis acids such as BF3 which only has 6 electrons.
no it does not follow octet rule
yes PCl3 obey octet rule there are 5 electrons in the valence shell of phosphorous it need 3 electron to complete its octet so it form bond with 3 chlorine after bond formation there are 8 electron in its octet it obey octet rule
because it does
Yes
H and I SCl4 ICl3 SeCI4 F2CCF2
I know for sure BBr# & PF5 do not obey the octet rule, but i can't remember the rule of isotopes so I can't say for sure whether or not CO3 -2 obeys it or not.
H and l
Chlorine Cl : it can have a higher valence (ClO2, HClO3) than predicted by the octet rule. Hydrogen H and oxygen O cannot escape the octet rule.
No. Some molecules, such as boron triflouride (BF3) and phosphorus pendachloride (PCl5) are octect violators.