Yes, CS2 Obeys the Octet rule. C double bonds with both Sulfur atoms and then each S has two pair of free electrons.
-4
Cl3CF
P certainly obeys the octet rule in phosphides: PH3, Na3P etc.
Xenon obeys octet rule and has a stable electronic configuration. So, xenon does not form any anion.
Yes, SO4 2- can be drawn without violating the octet rule. It is also a resonance structure. Here's an illustration below (ignore the dots, it was the only way it posted correctly!): .......O .......| O -- S -- O ....... .......O Hope this helped!
I know for sure BBr# & PF5 do not obey the octet rule, but i can't remember the rule of isotopes so I can't say for sure whether or not CO3 -2 obeys it or not.
-4
Cl3CF
because it has completely filled p orbital and obeys octet rule
No, Transition metals do not obey the octet rule in simple compounds , Am is an 'f' block transition metal.
H and I SCl4 ICl3 SeCI4 F2CCF2
Neon obeys the octet rule by not reacting and not forming ionic compounds as it already has a stable outer shell of eight electrons.
P certainly obeys the octet rule in phosphides: PH3, Na3P etc.
Xenon obeys octet rule and has a stable electronic configuration. So, xenon does not form any anion.
Xenon obeys octet rule and has a stable electronic configuration. So, xenon does not form any anion.
Yes, SO4 2- can be drawn without violating the octet rule. It is also a resonance structure. Here's an illustration below (ignore the dots, it was the only way it posted correctly!): .......O .......| O -- S -- O ....... .......O Hope this helped!
neon has completely filled orbitals, obeys octet rule and is stable. hence it is chemically inert.