Yes, Fe (iron) plus S (sulfur) equals FeS (iron sulfide). If the iron ion is iron(ll) then it is iron(ll) sulfide; if it is iron(lll), then it iron(lll) sulfide.
When CS2 is added to reaction mixture Fe + S = FeS , it would dissolve the excess 'S' leaving the solids Fe and FeS without any change.
Fe + S = FeS
Fe + S --> FeS
Fe + S ---> FeS
Displacement reaction , as HCl displaces S of FeS to give H2S
Two, iron Fe, and sulfur S.
FeS
S + o2 = so2
i think it fe+s=fes(iron dulphide)
Fe + S = FeS
ordinary mixing is a physical change but when you get to heat them products are formed and it is a chemical change.
Fe + S = FeS ---- 1) The first thing you need to determine is whether Fe or S is the limiting reagent. To do this you need the atomic mass of both Fe and S, which can be found on the periodic table. a) Fe = 56 and S = 32 Next, divide the given mass of the substance by the atomic mass. a) Fe = (25.0 / 56) = 0.4464 (moles of Fe) S = (32.0 / 32) = 1.0 (moles of S) Next, divide the number of moles of substance by the coefficient in front of the element (see the above chemical equation) a) Fe = (0.4464/1) = 0.4464 S = (1/1) = 1 Now you can see that the final number for Fe is smaller than the final number for S. This means that Fe is the limiting reagent and S is in excess. ---- 2) Now you can do a simple stoichiometry problem using Fe and converting to FeS. Always use the limiting reagent in the stoichiometry problem. Note: FeS = 88 (25) (1) (88) = 2200 = 25 (56) (1) 88 ---- The theoretical yield of FeS is 25g.