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Using Kepler's 3rd law of motion:

T2/a3=const.

T - orbital period

a - distance to the Sun

For Earth: T2/a3= 12/(1.5x1011)3=2.96x10-34

(11.86)2/a3=2.96x10-34

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a=780,095,402,531.93 meters = 5.2 AU

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Q: How can you find out the distance between the Sun and Jupiter Given is Jupiter's year is 11.86 Earth years and the distance between the Sun and the Earth is 1.5x1011 meters?
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