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This would be a fairly simple experiment to do. You place your water in a chamber which is pressurized (or de-pressurized) to the desired degree of pressure, then slowly heat it with a Bunsen burner until it starts to boil; a thermomenter in the water will then tell you the temperature.

If you just want the information, and don't want to do the experiment yourself, information about the boiling and freezing point of water at all different temperatures and pressures is given in what is known as a phase diagram. This can be found by way of Google under "water phase diagram" or in the Handbook of Physics and Chemistry.

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12y ago
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9y ago

Water boils at 100 degrees Celsius at 760 mmHg. By using the Clausius-Clapeyron equation and plugging in the known variables (To = 100, Tb = 81, Po = 760, Hvap = 40.68 kJ/mol), the answer is derived to be approximately 376 mmHg.

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12y ago

I assume that you are referring to the "normal" boiling point, i.e. the temperature at which a substance boils at either 1 ATM or 1 bar. Hvap (enthalpy of vaporization) can be found at different condition than the another temperature by the following method:

1) Use the heat capacity of the liquid to find the energy involved in taking the liquid from the temperature of interest to the boiling point temperature. If you have a formula then you have to integrate from the starting temperature to the boiling point temperature. If you have a constant (which is just a rough approximation of the average heat capacity over a range of temperatures) then just use

H = Cp(liquid)(Tboiling-Tinitial).

2) Add the heat of vaporization at the boiling point (Hvap)

3) Finally, add the enthalpy change for taking the vapor from the boiling point to the condition of interest. For an ideal gas, this would just be H = Cp(gas)(Tboiling-Tfinal). For real gases it is a little more complicated as you have to integrate PV over the change in pressure from 1 ATM (or 1 bar) to the final pressure. For an ideal gas, PV is constant so the integral is zero, but for real gasses with substantial pressure changes, the integral can be non-zero.

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14y ago

We can find the boiling point using the clausius clayperon equation .

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11y ago

You cannot. There is no simple relationship between the two.

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Q: What is the calculated atmospheric pressure in mm Hg if the boiling point of water boils at 81 degrees Celsius?
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