How Do you Convert 15v DC to 5v DC?

Answer 1

There are several ways. the most simplest is by using a single rectifying diode that only lets current pass in one direction. This is called a half wave rectifying circuit. You only get half the power also.

The second is by a full wave, or bridge rectifier which consists of 4 rectifying diodes which can usually be bought as a single package with 4 pins which are identified for correct connection. This allows the alternating cycle current to pass alternatively to the output pins in a push-push mode and maintains most of the current flow that you put into it.

The result is a very jerky or spikey DC current usually higher than the rated AC voltage. To smooth the spikes, extra circuitry is needed such as capacitors and maybe some smoothing coils but is way too detailed and varied for printing here.

Type in your browser "Rectifier Circuits" and you will find a smorgasborg of results where some will give a more comprehensive explanation of how AC is converted to DC.

Regards

Answer 2

24V to 12V 400W DC Inverter

24V to 12V 400W DC Inverter 24V to 12V 20A 400W DC to DC Inverter. Does little to change my PV system 12v 24v me the problem arose of what to do with investors who already had 12V. I was looking for a pattern online and found several schemes with linear regulators 20A, this solution although quite simple, due to the huge losses they have is not advisable. Ideally, a converter switched, high-performance. At the end I found nothing I liked and decided to design my own. Circuit characteristics: Output current: 20A at 12V (15A continuous and 30A Momentary), Input voltage: 18 to 30V DC, Output voltage: 5 to 20V, Operating Frequency: 70kHz, Effectiveness: 95%, 400W maximum power, Protections: Above current (30A) in the F1 circuit, D1 and F1 polarity in the circuit.

The circuit is designed to have the best performance with current components and quality, but at the same time as simple as possible and to be used in different applications such as solar or reducing voltages on 24V vehicles. The circuit begins with DC 24V power connector CN1, CN2 and the diode D1, the D1 is a protection against neglect by reversing the polarity. What is a regulator of type 7812, this circuit provides a fixed voltage of +12 V to power the IR2111 driver and the PWM module and temperature control.

The PWM module is responsible for providing the square wave pulse width modulated (PWM) on outputs S1, S2, this signal is proportional to the present intention in VSF points output circuit (output voltage source) and the entry module, these points are the positive feedback loop of the module, setting out the intention is achieved by varying the value of the trimmer P1 in the PWM module.

The temperature control module is responsible for maintaining the temperature of power MOS-FET and the circuit to an acceptable operating temperature, this control also reduces consumption and noise of the fan stopped keeping track when not necessary to its operation.

The amplifier is built around a driver for MOS-FET IR2111, this component contains within it everything necessary to drive and control in so -BRIDGE HALF the power MOS-FET. PWM signal enters the module pin (2) of IC1 by two diodes that mix the two output signals S1, S2 and the balancing resistor R3, the resulting signal is a square wave with a fixed frequency of 70kHz modulated width from 0% to a maximum of 98% depending on the intention +12 V.esta output square wave signal is amplified by the power stage T1, T2, T3, is filtered by the inductor L2, built with a core ferrite toroidal high value type, this type is used very often in the power supplies switched to filter the type of outings and intentions as far as possible eliminate the AF component (high frequency) of the ongoing intention of leaving the source. After the intention L2 is rectified by a group of diodes D10, D11 high-performance type Schottky , diode cough is characterized by low internal resistance and high operating frequency to be suitable for applications in switching power supplies. To finish is filtered and stabilized by two capacitors electrolytic C10 , C11. The end result is a power supply voltage quality and very stable.

COMPONENTS

CONDENSADORES

C1 = 220 uF 35V

C2, C3, C7, C12 = 100nF

C4 = 10uF 35V

C5 = 63V 6800uf

C6 = 100uF 35V

C8 = 2Uf 250v

C9 = 1uF 100V

C10, C11 = 3300 uF 25V

RESISTANCE

R3, R7 = 1k 1/4W

R4, R5, R6 = 22 1/4W

SEMICONDUCTORS

VR1 = UA 7812

INTEGRATED REGULATOR +12 V

D1 = BY255

RECTIFIER DIODE 3A

2, D5, D6 = UF4002

DIODE FAST 1A

D3.D4, D8 = 1N4148

SMALL SIGNAL DIODE FAST

D7, D9, D14 = UF4006

DIODE FAST 1A

D10, D11 = STPS4045CW

DOUBLE DIODE Schottky

45V 40A

IC1 = IR2111

FOR MOS-FET DRIVER

T1, T2 = APT10M25BVR

MOS-FET 100V 70A

T3 = IRL2203

MOS-FET 30V 116A

Sundry liabilities

F1 = 30A

CAR FUSE 30A

L2 = 100UH 25A SHOCK

3 WINDINGS DOUBLE GLAZED FOR 1.2mm WIRE CORE TYPE ON

ARISTON BLS1/NTF311

Detail of part of the track in the PCB where you can see components T3, R6, D8 Bridge heat sink and T3 that are welded directly to printed circuit track.

Picture where you can see the reinforcements made with tin to copper traces on the printed circuit to withstand the large currents flowing through them.

Picture of the completed circuit and testing it.

24V to 12V 400W DC Inverter

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Answer 3

As a voltage reference you could use a variable potentiometer or a fixed resistor bridge.

For a power supply delivering low current, there are a variety of fixed voltage power supply ICs to do the job, the best known being the 7805 series. There are several types with different output currents and different input voltage limits. They require just one or two capacitors to operate and deliver a stable output voltage. Their disadvantage is that being linear, they will dissipate twice as much power as heat as they deliver to the load with a 15V supply. This can be reduced by reducing the incoming voltage or by using a switching power regulator.

Switching regulators are often known as "buck converters". Using high frequency switching they allow current from the input to flow to the output whenever the output voltage drops below a certain threshold then turn off as the voltage rises above another threshold. (This description is not fully accurate but suffices for this answer). In this manner, the regulator does not draw current from the incoming supply continually and they are as high as 90% efficient. This is a much better arrangement if the power supply is to drive a high current load.

Answer 4

Best thing to use, (well, at least the quickest) is a DC to DC converter module.

Answer 5

Vrms = Veff = 0.707Vp== With the use of a voltage rectifier.Full wave Rectification can be used to convert AC voltage to DC ie simply put diode we convert