You can also get 6 pieces by rearranging between the cuts. Put the donut flat on the table and make a downwards cut through the center. That gives you two C shapes. Align one on top of the other and make another downward cut, slicing off the 'prongs'. So you get 4 prong pieces plus 2 attenuated C shapes.
Source https://www.physicsforums.com/threads/slice-the-donut.36089/
You start by cutting the doughnut in half lengthwise , take those two pieces & fold them in half , then stack them on one another , and make two intersecting cuts from above your stack , that should give you twelve pieces, what this accomplishes is another ?
1.) Cut the cake in half through the center (so that it creates a top and a bottom half). 2.) Cut the cake in half across the center (from the top down) widhtwise. 3.) Cut the cake in half across the center (from the top down) lengthwise.
You cut it three times until you get twelve pieces! ha' your welcome . :D
You would cut it into 4 pieces and then you would cut through the middle.
I like the answer here:
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Maximum number possible is five pieces by making two lines that border the hole in the center and intersect near one end.
yes, two on top to make an x and one through the side to cut those 4 pieces you just made into 8.
Lay the bananas next to each other then cut through all the bananas together. By making three cuts you will get nine pieces of banana.
use a cutter
Eight. Use the first two cuts to cut the pie into four pieces, then use the third cut to slice the top from the bottom, doubling the number of pieces to 8.
Cut a pizza into 2 using one straight cut. Stack the pieces and make a straight cut: you now have 22 = 4 pieces from 2 cuts. Stack these and make a straight cut: you now have 23 = 8 pieces from 3 cuts. Continue. After 7 cuts you can have 27 = 128 pieces. You can reduce the number of pieces to 29 if, after the fourth cut, you stack and cut only 11 pieces and thereafter cut just one each time. There are other options which give the same result.
Make two cuts normally, then make the third cut along a line that crosses both of the first two cuts but does not pass through their intersection.
A log would need three cuts to make four pieces. Here are 4 pieces. The "." represents each of the cuts. =.=.=.= So, 3 cuts at 3.20 per cut is 9.60 3 x 3.20 = 9.60
This is impossible for any convex shape, so one will need to exploit the non-convexity of a bagel. The first cut needs to be such that two u-shapes are left. This is achieved best if the cutting plane is tilted with respect to the planes of symmetry of the bagel. Now, stack the two u-shapes and cut them both into three pieces using 1 cut, cutting of the 'legs' of the u's. Now we have 6 pieces and 1 cut to go, so stack all the pieces and cut right through to give 12 pieces in three cuts.
Cut a round cake in eight equal sized wedge shaped pieces with four vertical cuts, then make one horizontal cut through the center of the cake to equal sixteen pieces.It's slightly more tricky if you are only allowed to cut the horizontal cross-section of the cake (treat the cake as a circle). In this case, first divide the cake with one cut (2 pieces), then cut it again so that it intersects the first cut (4 pieces), then cut it a third time so that it intersects both cuts previously made, at different points (7 pieces), then let the fourth cut intersect all three cuts so far at different points (11 pieces), and let the fifth and final cut intersect all four cuts at different points (16 pieces total).
the normal amount would be 17
As no constraints on the shape or regularity of the resulting pieces are made, making a three by tree line grid on the pie surface would result in 16 separate pieces. Cutting the pie into regular wedges with 6 straight cuts passing through the center would result in 12 pieces.
If no cut intersects any previous cuts, then you can just slice it into 14 pieces.
Platelets are the cell pieces that form clots and seal up cuts.