# How do you find the distance from the origin to a point on the graph?

# How do you find the distance between two points?

For two coordinates points (x 1 , y 1 ) and x 2 , y 2 ), you can find the straight line distance using the Pythagorean theorem. The vertical difference (y 1 -y 2 ) forms one side of the triangle, and the horizontal difference is the other (x 2 -x 1 ). The hypotenuse is the straight distance along t…he line, and is defined by : h = square root of (a 2 plus b 2 ) = square root of [ (y 2 -y 1 ) 2 + (x 2 -x 1 ) 2 ] --- EXAMPLE : For points (1, 3) and (4, 7), the distance along y is (7-3) and along x is (4-1) and square root [ 4 2 + 3 2 ] = sq rt [9 + 16] = sq rt [25] = 5. Measuring the distance along the line would verify that the distance is 5. (MORE)

# A single point on a distance time graph tells the?

The vertical axis gives the distance of an object from a fixed point - the point of reference - after a time, as measured on the horizontal axis.

# How do you find a midpoint between two points on a graph?

Given two coordinates (x 1 ,y 1 ) and (x 2 ,y 2 ) The midpoint is ( ((x 2 +x 1 )/2) , ((y 2 +y 1 )/2) )

# How do you find the distance between two points on a graph?

The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..

# How do you find the function of a curved graph based on a set of points?

Given a set of n points it is possible to find a polynomial of order n-1 to fit them. So if we have 3 points, that means there's a polynomial of order 2 that will pass through all the points. A polynomial of order 2 is also known as a quadratic, or parabola. Let's use an example to illustrate: … Take the 3 points (0,0), (1,1), (2,0) Then these will fit a curve with the equation y = ax 2 +bx+c If we put the first point into this equation (y=0, and x=0), then that means: 0 = 0+0+c so c=0. The second point (y=1, and x=1) shows us that: 1 = a.1+b.1+c = a+b (since c=0). so 1 = a+b. The third point says that: 0 = 4a+2b, so b = -2a. We now have a simultaneous equation in a and b. (1): a+b=1 (2): b=-2a These can easily be solved by substitution giving: a=-1, b=2 Therefore we have the curve y = -x 2 +2x which fits the three points given above. Technical note: It can be the case that the polynomial required has an order of less than n-1 for n points, but it will never be more. (MORE)

# How do you find the distance between points?

Use the distance formula. SQRT( (y1-y2)^2 + (x1-x2)^2) ) . You can also try a website called meetways (see related link below). They will do the math equation for you, simply enter the two points and then hit the "Find Halfway Point" button. You can also add a point of interest and meetways will dis…play a businesses near the halfway poit based on your query. (MORE)

# How do you find coordinates of two points to find distance between them?

Use the distance formula. SQRT( (y1-y2)^2 + (x1-x2)^2) ) x1 and y1 are the first coordinate pair x2 and y2 are the second coordinate pair

# What is the distance between the origin and the point 5 -19?

The distance is 19.65 (rounded). The leg distances are 5 and 19, respectively, and the diagonal is the square root of the sum of the squares. 5 2 + 19 2 = 25 + 361 = 386, and sqrt 386 = 19.6468 about 19.65 .

# How do you find distance on a velocity time graph?

Assume time = horizontal (x) axis, and velocity = vertical (y) axis..
(Actually we should call it 'speed', since the graph conveys no information about the direction of the motion, only the speed. Similarly, the distance we'll find won't tell you how far from the starting point you wound up, only h…ow much road or track you covered.).
On the graph, there is some straight or wavy line representing your speed at every instant..
-- Pick the starting time and ending time of the interval you're interested in. Draw vertical lines on the graph at the starting and ending times, long enough to cut the wavy line that represents the speed function..
-- From the value of the function at the start-time, (the point where the 'start' vertical line cuts the graph of the function), draw a horizontal line, all the way across, to the 'end' vertical line..
-- Now you must measure the area of the space bounded by the speed graph and the three straight lines you have drawn. This is easier if the graph was drawn on paper that is marked off in a grid of small squares..
There may be places where the function is below the horizontal line, as well as places where the function is above it. If so, list the area of the space where the function is below the horizontal line as a negative number..
-- When you're done, add up all the positive and negative pieces of area you have measured. The result is the total distance that the moving object traveled during the time between the 'start' and 'end' lines. (MORE)

# How does one find out if an equation's graph goes through the origin?

-- Take the equation -- Set either 'x' or 'y' equal to zero -- Solve the resulting equation for the remaining variable -- If the remaining variable is then also zero, then the origin is on the graph of the function If the graph is a straight line ('x' and 'y' appear in the equation only …to the 1st power), then the equation has to be in the form of a simple ratio ... like (y = Kx) or (x = Ky) or (xy = K) or (x/y = K) ... in order to go through the origin. (MORE)

# Find the coordinates of a second point on the graph of a function f if the given point is on the graph and the function is even?

If the point (x,y) is on the graph of the even function y = f(x) then so is (-x,y)

# What is the origin of a graph?

The origin of a graph is the point specified by the ordered pair (0,0). It is where both the x-coordinate and the y-coordinate are zero and their respective axes intercept.

# The slope at any point of a distance-time graph repersents what?

The slope of the line is equal to the velocity of the object. Since the slope of a line is determined as rise over run, the slope of this line would be meters over seconds. This is the unit for velocity, m/s. rise/run = meters/second The labels on the graph will give you much more information than… you think. (MORE)

# What is the distance between the origin and the point 8 -17?

For any two points, (x1, y1) and (x2, y2), the distance is SQRT[(x1 - x2)2 + (y1 - y2)2] In this case, the distance is:[ 82 + (-17)2 ] = sqrt (353) = 18.79 (rounded)

# A single point on a distance time graph tells what speed?

x axis = time, y axis = distance since magnitude of velocity (speed) = distance / time the gradient of a tangent of the line at any point represents instant magnitude of velocity (speed).

# Do graphs make it hard to find the main point of some data?

Only if they are badly presented graphs or if the person viewing them is not a visual person.

# How do you find distance between two points?

If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x 2 - x 1 ) 2 + (y 2 - y 1 ) 2 ). If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x 2 - x 1 ) 2 + (y 2 - y 1 ) 2 ). If you know the coordinates, use the Pythagorean Theorem…: take the square root of ((x 2 - x 1 ) 2 + (y 2 - y 1 ) 2 ). If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x 2 - x 1 ) 2 + (y 2 - y 1 ) 2 ). (MORE)

# How do you find an exact data point on an Excel graph?

Excel 2007 does not have this capability. Excel 2003 can do this as described in the related link. The idea is to draw your graph, then overlay a non-related point on the graph. When you drag the non-related point to the location on the graph where you want to identify a data point, you will see th…e underlying cell reference change to the location of your selected data point. (MORE)

# How do you graph points?

To graph points, use rise over run and go up and over on the graph

# How do you find the distance between two endpoints on a graph?

-- take the difference between the 'x' values of the two points; square it -- take the difference between the 'y' vales of the two points; square it -- add the two squares together -- take the square root of the sum The result is the distance between the two points.

# What is the distance between the origin and the point 5 12?

For any two points, (x1, y1) and (x2, y2), the distance is SQRT [(x1 - x2)2 + (y1 - y2)2] Here, x1, y1 = (0, 0), so distance = sqrt(52 + 122) = sqrt(25 +144) =sqrt(169) = 13

# Distance from origin to point?

The origin on a graph is the point (0,0). You can find the distance to a point by applying the Pythagoreantheorem: Square the x coordinate and add it to the square of the y- coordinate of the point. Now take the square root of your answer. The result is the straight line distance from the orig…in to thepoint. (MORE)

# How do you find the distances between two points?

The question is not well specified and so there are several possible answers. In n-dimensional Euclidean space, if the coordinates of the two points are A = (a 1 , a 2 , ... a n ) and B = (b 1 , b 2 , ... b n ), then the minimum distance AB is given by AB 2 = (a 1 -b 1 ) 2 + (a 2 -b 2 ) 2 + …... + (a n -b n ) 2 In 2-dimensional space, this reduces to AB 2 = (a 1 -b 1 ) 2 + (a 2 -b 2 ) 2 On a spherical surface, such as the surface of the earth, the shortest distance between two points is along the arc of the great circle: a circle whose centre is the centre of the sphere and whose circumference passes through the two points. The shortest distance on the surface of a polyhedron may be found by finding the straight line distance between the images of the two points on its net. Finally, there are other ways of measuring distance. One that is fairly easy to understand, is the Minkovski or taxicab metric (or the Manhattan metric). If you want the distance between two points in a city it is not much use to be told the distance "as the crow flies" - unless you happen to be a crow. What you want is "go x blocks North and then y blocks East": that is a distance of x + y blocks rather than sqrt(x 2 + y 2 ) blocks! (MORE)

# What does a single point on a distance time graph show?

The distance from start at which a certain object is located at a certain time.

# What is the distance between the origin and the point 5 19?

The distance is 19.65 (rounded). The leg distances are 5 and 19, respectively, and the diagonal is the square root of the sum of the squares. 5 2 + 19 2 = 25 + 361 = 386, and sqrt 386 = 19.6468 about 19.65

# What is the distance between the origin and point 5 ans -2?

D = sqrt[(Y2-Y1)^2 + (X2-X1)^2] Geometrically points are: (0,0)(5,-2) D = sqrt[(-2 - 0)^2 + (5 - 0)^2] D = sqrt(29) ~ 5.385

# What does a distance time graph allow you to find?

Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.

# How do you find the point of intercept of two equation without graphing it?

The two equations must involve 2 unknowns. If there is only 1 unknown, the 2 equations must be the same (or one a simple multiple of the other). Using one of the equations, turn it into a form where one of the unknowns is expressed in terms of the rest of the equation. Then use this expression to su…bstitute for that unknown in the other equation. This other equation now involves only one unknown so you can simplify it to find its value. Use that value in either of the original equations to find the other value. Example 2x + 3y =8 and x-y=-1. From the 2nd equation you have x=y-1 and use that in the 1st equation to get 2(y-1)+3y=8, which depends only on y. Simplify to get 2y-2+3y=8, so 5y=10 and y is 2. Use that in either of the 1st pair of equations to get 2x+6=8 (or from the other equation x-2=-1) Either way, x=1. (MORE)

# Why do you need to find the inflection point on a graph?

To find the inflection points on a graph, you need to take the second derivative. Then, set that equal to zero to find the x value(s) of the inflection point(s).

# How do you find the distance between the origin of a cartesian coordinate system and a point?

To find the distance between the origin and the point (x,y) use Pythagoras on the right angled triangle which has the points (0, 0), (x, 0), (x, y) - the distance is the hypotenuse of the triangle and so has length: distance = Ã¢ÂˆÂš(x 2 + y 2 ) .
This can be extended to find the distance betw…een any two points (x 1 , y 1 ) and (x 2 , y 2 ): distance = Ã¢ÂˆÂš((x 2 - x 1 ) 2 + (y 2 - y 1 ) 2 ) .
(for the original question (x 1 , y 1 ) is the origin (0, 0) and the first formula results.) (MORE)

# How do you find an object's instantaneous on a distance vs time graph?

With great difficulty since the question does not specify what aspect of the object's instantaneous. Speed, position, acceleration?

# How do you find the lowest point on a linear graph?

Lines are infinite and so do not have a highest or lowest point. You need to have a curve to have a possible lowest point.

# What is the distance from the graph of a number to the origin on a number line?

The distance from a number on a numberline to the origin, is called the absolute value .

# How do you find the roots of a polynomial of graphed points?

Join the points using a smooth curve. If you have n points choose a polynomial of degree at most (n-1). You will always be able to find polynomials of degree n or higher that will fit but disregard them. The roots are the points at which the graph intersects the x-axis.

# How can you use a graph of earthquake waves travel distance and time to find an epicenter?

Not easily because .
The speed at which waves travel depends on the medium that they are travelling through. For example, the speed is affected by whether or not the wave travels through the mantle or the core. .
The waves are often reflected back to the surface from the core-mantle boundary. . …
The direction of the wave is affected by diffraction because its speed of propagation varies with the density of the medium. But there are statistical models being developed to get around these problems. (MORE)

# What is the distance between the origin and the point 8 17?

Distance = sqrt(8 2 + 17 2 ) = sqrt(64 + 289) = sqrt(353) = 18.79 That would be points (0, 0) and (8, 17) Distance = sqrt[(Y2 - Y1) 2 + (X2 - X1) 2 ] Distance = sqrt[(17 - 0) 2 + (8 - 0) 2 ] Distance = sqrt(17 2 + 8 2 ) Distance = sqrt(289 + 64) Distance = sqrt(353)

# What is the distance between the origin and the point -5 19?

The distance is 19.65 (rounded). The leg distances are 5 and 19, respectively, and the diagonal is the square root of the sum of the squares. 5 2 + 19 2 = 25 + 361 = 386, and sqrt 386 = 19.6468 about 19.65

# How the velocity - time graph can be used to find the distance traveled by the body in a given time?

Sure. By finding the area under the curve within the limits of time, we can find the distance covered in that time duration. Since v = ds / dt, ds = v dt. So for small time gap dt, vdt gives the displacement ds. So by integrating vdt for the limits, we can get the total displacement S

# How do you find the distance from a velocity time graph?

Displacement is the area under the velocity-time graph. Refer to the related links for more information.

# How do you find points on a parabola to graph them?

Select a set of x values and find the value of y or f(x) - depending on how the parabola is defined. These are the values that you need to graph.

# How do you find distance in a speed time graph?

The distance from the origin at time t, in the direction of motion, is the area under the graph between time 0 and time t. In a simple speed-time graph the area may be calculated using simple formulae for the areas of triangles, rectangles, trapeziums. In more complicated cases you will need to int…egrate for the area under the speed-time curve. And in seriously complex cases, you will have to use numerical estimation for the area. (MORE)

# What does a single point on a distance time graph tell you?

It tells the time and location of the object that you are tracking at one point in time.

# What is the distance of point p -6 8 from origin?

The distance from the origin {0;0} to {-6;8} is: SQRT ((X 2 -X 1 ) 2 + (Y 2 -Y 1 ) 2 ) SQRT(-6 2 +8 2 ) = SQRT (36+64) = SQRT (100) = 10 (Exactly) Answer: 10

# How do you find an exponential equation from two graph points?

I assume you're fitting an relation of the form y =ae bx . Take the natural logarithm of both sides of the relation: ln y = a+ bx (1). Suppose your points are (-1, 7.39) and (1,0.14). Because we have arelation between the logarithms of the y co-ordinates and the xco-ordinates themselves let us rep…laces the y co-ordinates withtheir logarithms to obtain the points (-1, 2) and (1, 2). Now wecan use this points to obtain two simulaneous equations in thetransformed equation (1) and solve it as usual to obtain a = 1 andb = -2. The fitted relation is y = e -2x . (MORE)

# Why is it important to start at the origin when you are graphing points?

It is important for beginners because the coordinates of the graphing points are measured from the origin. More expert users don't need to do so.

# When you take the slope of a distance-time graph you find?

If Distance is the ordinate(y-axis) and Time is the abscissa(x-axis) then the slope gives the speed. If Time is the ordinate(y-axis) and Distance is the abscissa(x-axis) then the slope gives the Time taken per unit of Distance

# How can you find the unit rate from a line on a graph that goes through the origin?

It is the gradient of the line. Pick any two points on the line. Measure the RISE = difference in their heights (distances from the x-axis), and the RUN = difference in their horizontal displacements (distances from the y-axis). The unit rate is RISE/RUN.

# What is the distance between the origin and the point (5 -19)?

It works out as the square root of 386 which is about 19.647 rounded to 3 decimal places

# If you know two points on a line how can you find the rate of change of the variables being graphed?

If the cordinates of the two point are (a, b) and (c, d) , then: Rate of change is "rise"/"run" = (b - d)/(c - a) = (d - b)/(a - c)

# What is the distance between origin and the point (8-17)?

Points: (0, 0) and (8, -17) .
Distance: square root of 353 or about 18.788 rounded to 3 decimal places