answersLogoWhite

0

How do you integrate x power x?

Updated: 4/28/2022
User Avatar

Wiki User

12y ago

Best Answer

e^x/1-e^x

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you integrate x power x?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Integrate x 5x dx?

integrate(x5x dx) simplifies to integrate(5x^2 dx), and using the power rule of integration, add one to the power of x and divide the term by that number. Thus, x5x dx integrated is (5/3)x^3


How do you integrate x power -1?

x-1 = 1/x ∫1/x dx = ln x + C


What would be the integral of x where x has power 2?

If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.


Find general solution of x to power of 3 dp divided by dx equals a minus x?

I can't integrate a-x /x-3 ?


What is an example of intergrate?

integrate of x is 1/2x^2. integrate of 1 is x


How do you integrate x power e power x?

{xe^x dx integrate by parts let f(x) = x so f'(x) = 1 and g(x) = e^x so g'(x) = e^x so.. f(x)*g(x) - {(g(x)*f'(x)) dx therefore xe^x - {(e^x * 1) dx so.. xe^x - e^x + C factorize so... (x-1)e^x + C


What is integration of x to the power x with respect to x?

Apparently that can't be solved with a finite number of so-called "elementary functions". You can get the beginning of the series expansion here: http://www.wolframalpha.com/input/?i=integrate+x^x


Integrate 10 divided by x square?

-(10/x)


How do you integrate 2sinxcosx?

Integrate 2sin(x)cos(x)dxLet u = cos(x) and du = -sin(x)dx and pull out the -2:-2[Integral(u*du)]Integrate with respect to u:-2(u2)/2 + CSimplify:-u2 + CReplace u with cos(x):-cos2(x) + C


Integrate square root X 4X from 1 to 2?

root x=x^(1/2) and 4x =4 x^1 you add the exponents then integrate as usual. The answer you should get is 4.


How do you integrate functions?

To integrate a function you find what the function you have is the derivative of. for example the derivative of x^2 is 2x. so the integral of 2x is x^2.


How do you integrate xe power x?

Use integration by parts. integral of xe^xdx =xe^x-integral of e^xdx. This is xe^x-e^x +C. Check by differentiating. We get x(e^x)+e^x(1)-e^x, which equals xe^x. That's it!