How do you prepare a 1N HCl solution?

Answer 1

dilute 85ml of HCL to 1000ml This answer does not state which is the original concentration of the 85ml of HCL mentioned. The question should state what does the operator have initially (for example "I have HCl 87.5% (v/v; 7+1) solution and I want to get 1N solution of HCl, what should I do?"

Answer 2

37% HCl means 37 gms /100mL or 370 gms /litre.That means 370/36.5 M.Now to convert it to 0.1N HCl.

The normality and Molarity for HCl is same as HCl is a mono protonic acid.It means we have 370/36.5 N HCl.

Using N1V1 = N2V2;

Here N1 =370/36.5N, V1 = ? ( to be calculated);

N2 =0.1N , V2 = 1000 mL ( Assumed ) it can be any value you desire );

Or ( 370/36.5)N *V1 = 0.1N *1000

or V1 = 0.1N*1000/(370/36.5)N;

or V1 = 0.1*1000*36.5/370;

or V1 = 9.86 mL or 8.9mL;

So take 990.1 mL of water and mix 9.9 mL of acid in it to get 1000mL of 0.1N HCl.

Answer 3

Density of HCl: 1.48 g/ml

Molecular weight of HCl: 36.5g/mole

Concentration of HCl stock: 36%

Concentration of another HCl stock: 12N

Final volume: 1L

Let's assume that we're making a 1N HCl solution. Using the 36% concentration stock, we'll need to find out how many ml we would need. However, HCl is interesting because it has a higher density than water.

For a 1N solution (also known as 1M) however, you would need this amount of grams:

(1M HCl) x (36.5 g/ mole HCl) x (1L) = 36.5 grams.

Now we need the amount of ml from a 36% solution. This is different from having a known concentration like 10M, for example.

36% = 36 grams HCl / 100 grams of stock concentration solution

(36.5 grams HCl) x (100gram of stock solution/ 36 grams HCl) x (1 ml/ 1.48 grams) =

68.5ml

Dissolve 68.5ml of 36% solution into 931.5ml of ddH20.

If your stock concentration came in 12M, then using the following equation:

M = concentrations and V = volume.

M1V1 = M2V2

V1 = (M2V2 )/M1

Using the second equation,

V1 = volume of your stock concentration

M1 = concentration of your stock

V2 = volume of your final preparation

M2 = concentration of your final

V1 = (1 M x 1L )/(12M) = 0.083 L = 83ml

Dissolve 83 mL of 12M HCl into 917ml of ddH2O

Answer 4

Typically, to prepare 0.1 M HCL solution you will need to dilute it from the stock solution or concentrated HCL. I assume that you use concentrated HCL. Most concentrated HCL exist in 37.5%

As far as we know, 37.5% concetrated HCL is not a pure HCL. So, we need to do a bit of calculation to dilute it to the desired concentration. There are many ways of calculation but instead I will use the accurate calculation which is the Normality calculation for dilution.

The calculation method:

Grams of compound needed = (N desired)(equivalent mass)(volume in liters desired)

Volume of concentrated acid needed = (grams of acid needed)/(percent concentration x specific gravity)

Before we begin, you need to know what is Normality (N). Normality is used to measure the concentration of acid or base in the solution. Normality is similar to molarity as molarity measure the concentration of ions or compounds in a solution while normality represent the molar concentration of acid component or base component.

To know the normality, simply multiply the molarity with the number of hidrogen ions (H+) in the acid solution or hydroxide ions (OH-) in the base solution.

(*HCL only has 1 hidrogen ion)

Now to dilute 0.1 M HCL from 37.5% concentrated HCL solution, you need to find the normality first. Simply multiply 0.1 M with 1 will give you 0.1 N.

The equivalent mass is the molar mass divided by by the number of hydrogen ions.

Molar mass for HCL is 36.4611 g/mol. Since HCL only has one hydrogen ion, the equivalent mass will be 36.4611. The volume will be in 1 litre. HCL specific gravity is 1.189.

Insert the details in the formula,

Grams of compound needed = (0.1 N)(36.4611)(1 Litre) = 3.6461

Volume of concentrated acid needed = (3.6461)/(0.375 x 1.189) = 8.1774 ml

So, 8.1774 ml of 37.5% concentrated HCL is needed to prepare 0.1 M HCL.

Answer 5

To prepare 1N HCl take 8.33 ml of 12N HCl and make up to 100 ml

Answer 6

add 8.28ml of 37% HCL in 100 ml distilled water to prepare 1N HCL solution!

Answer 7

if you want to 250ml 1M of hydrochloric acid ,you need to add 21ml 12M(37-38%)hydrochloric acid to 229ml water

Answer 8

1M=36.5g in 1000ml water,3M=109.5g in 1000ml=10.95g in100ml

Answer 9

Use C1V1 = C2V2

Answer 10

Preparation of 10 ml of 1 N H2SO4