How to Change lower case to upper case in C plus plus?

Answer 1

Char 'a' is 97 decimal (61 hex) while char 'A' is 65 decimal (41 hex), a difference of 32 decimal (20 hex). Therefore test each char value in the char array (or string) using a for loop. If the char value is in the range 'a' to 'z', then subtract 32 decimal (20 hex).

The following example demonstrates the method:

void toupper(char* str, int len)

{

for(int i=0; i<len; ++i)

{

if(str[i]>='a' && str[i]<='z') str[i]-=32;

}

}

To convert from upper to lower case, use the following instead:

void tolower(char* str, int len)

{

for(int i=0; i<len; ++i)

{

if(str[i]>='A' && str[i]<='Z') str[i]+=32;

}

}

Answer 2

Subtract 32 from each character in the range 'a' to 'z', inclusive. C++ will convert these literals to their equivalent ASCII code. Note that ASCII code 'A' is 32 less than ASCII code 'a'. Decimal 32 is 0x20 in hexadecimal notation, and 0x40 in octal.

To convert to lowercase, add 32 to characters in the range 'A' to 'Z', instead.

Answer 3

#include<stdio.h>

main()

{

char str1[]="PIYUSH";

char str[20];

str2=strlwr str1;

printf("%s", str2[30]);

}

Answer 4

If the character is greater than or equal to 'a' and less than or equal to 'z' then subtract 32 from the character. Note that 'a' is ASCII code 97 while 'A' is 65, therefore 97-65=32.

Answer 5

Sure. But it would be more correct to say 'lower case letters' and 'upper case letters'.

Answer 6

void ToUpper (char* string) {

while (*string != '\0') {

if (islower(*string)) *string = toupper(*string);

}

++string;

}

Answer 7

toupper()