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Since Heptane has a boiling point of 98 degrees Celsius, and Heptanol has a boiling point of 176 degrees Celsius, you'd evaporate or boil the Heptane and Heptanol mixture to around 120 degrees Celsius. Which would leave the Heptanol behind and have the Heptane evaporated.

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8y ago
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13y ago

Distillation will do it. It is the process of separating a mixture of compounds with different boiling points. n-heptane has a boiling point of 98oC & n-heptanol has a boiling point of around 175oC.

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7y ago

Heat the mixture. At 98 deg C, the heptane will start boiling off along with some evaporating heptanol. The temperature will remain at 98 deg until all the heptane has boiled off. The temperature of the liquid will then start rising again. Stop heating, and condense the vapours in a separate container.

The liquid remaining in the original container will be pure heptanol. The condensate will be mainly heptane with a bit of heptanol. Repeat the process to obtain greater purity of heptane.

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15y ago

you would use the boil it to about 110c and the heptane will evaporate leaving the heptanol

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9y ago

A mixture of heptane and heptanol can be separated through fractional distillation. This is possible because of the elevated boiling point of heptanol compared to heptane.

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14y ago

phase separation. the two solvents must have similar polarities and b.p.'s - no crystals would form...and if for some reason they did, they would be impure

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15y ago

DIstillation

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Q: How would you separate a mixture of heptane and heptanol at boiling point?
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I will simple use the distillation method. That is I will separate the mixture of soluble from its solution when the solvent is to be recovered; heptane being more volatile (boiling point 98 degree) goes out first before heptanol (less volatile higher boiling point 176 degree)


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