I have the feeling that you were looking to find a value for each variable in this equation. Unfortunately you can only solve for each variable in terms of the other variables in this equation.
0 ,2 , 3 and 7
0,2,3 and 7
Solve the following equation for A : 2A/3 = 8 + 4A
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
Since this is a linear equation with 2 variables, it is an unsolvable equation as a and b could be anything, to find an exact answer you need another equation that relates to the first one.
2a = 35 a = 35/2 a = 17.5
If: 2a+13 = 5a+1 Then: a = 4
Solve the following equation for A : 2A/3 = 8 + 4A
Solve the following equation for A : 2A/3 = 8 + 4A
a=10
2ab - 3b2 - 3b + 2a does not have a solution, as it is not an equation.
3a x 2a =24
a = 4
-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2
2a^3=8+4a2a^3-4a-8=0 a^3-2a-4=0 It occurred to me just now by looking at the equation that a=2 would work. And it does. So that's your answer.
14!!
2a/3=8+4a2a=3(8+4a) 2a=24+12a -10a=24 a=-24/10 a=-12/5
We have, 2a + 24 = 30or, 2a = 30-24or, 2a = 6or, a = 6/2 = 3.Therefore, a equals 3 or simply a=3