This is a question of permutations. It is equal to 3! / (3 - 2)! = 3! / 1! = 6/1 = 6. If you want to check this, you can actually create the numbers yourself, since there aren't that many: 46, 48, 64, 68, 84, 86.
It is 120 if the digits cannot be repeated.
There are 3,265,920 numbers that can be formed using all the digits. The answer to the question will depend on which one of these.
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
36
6*6*3 = 108 numbers.
There are 2000 such numbers.
There are 2000 such numbers.
The number 1234567890 can create about 39 of 40 4 digit numbers.
numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4
Assuming the question refers to the digits 1, 2, ... , 9 the answer is 1344 numbers.
16, multiply the number of numbers there are in the set by itself
Just six numbers... 345, 354, 435, 453, 534 & 543