answersLogoWhite

0


Best Answer

2048/128 = number of chips.

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many IC required to obtain 2048 8 memory using 128 8 memory chip?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many address lines are required if micro processor has to access 2kb memory?

2kb=2*1024=2048 2^11=2048 therefore 11 address lines are required


How much memory would be required to process a digital image with a matrix size of 2048 x 2500 using a bit depth of 12?

2621440000 B or 2621440 KB


Specify the number of registers in a 2k memory chip?

1kb=1024 byte is multiply by the total memory which is given to you as bellow: (1024*2) = 2048 register


How many register in 2K memory chip?

Registers represent the number of memory locations. A 2K memory chip has 2x1024=2048 memory locations. Hence there are 2048 registers in a 2K memory.


How many nuMBer of address lines required for 8 MB of memory?

It takes 23 address lines to address 8 mb of memory.


How many MB are in a 2GB memory card?

1024 MB = 1 GB 1024 MB X 2 = 2048 MB = 2GB Answer - 2048 MB 1024 MB = 1 GB 1024 MB X 2 = 2048 MB = 2GB Answer - 2048 MB


How many 1288 RAM chip are needed to provide a memory capacity of 2048 bytes?

16


Is 512MB more than 4GB?

No. 2 Gb is 2048 Mb. 2Gb is four times the memory of 512Mb.


2048 + 2048 = What is the answer?

4096


What is the RAM and hard drive memory?

This computer's memory type is: DDR2 SDRAM, with a hard drive capacity of 160GB (solid state disc flash memory). For further reference the cpu speed is 1.60 Hz and internal memory is 2048 MB.


How many adder are reuired to realize 256 point radix 2 fft using dit?

ans: 2048 bcz, N=256therefore, adders= N*log2N=2048


How many slots are open for RAM upgrades on the HP Mini Netbook?

There is only one accessible memory slot on the HP Mini Netbook. Maximus supported memory is 2048 mB.