There is a misconception that a step-up transformer 'steps up voltage, but steps down current'. Nothing could be further from the truth!
The secondary current of any transformer is determined by the secondary voltage and the load which it supplies. It is NOT determined by the primary current!
In fact, it is the primary current that is determined by the secondary current -not the other way around.
So, to answer your question, your step-up transformer has a voltage ratio of 1:2.3, so the primary current that results from a secondary current of 150 A must be 2.3 x 150 = 345 A.
Power= voltage x Current
current= power/voltage
therefor current = 1500/208 ( power = 1500 watt, voltage= 208 volt)
=7.211Amp
what is the fault in the transformer, it trips when it is charged.it is charged through the 100 amps MCCB.
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
On a 1kva you have 1000 watts capacity. To fine the current the formula is I = W/E. The secondary side of the transformer has the capacity of 1000/120 = 8.3 amps. In your question you do not put the amps across the secondary you draw amps from it. Using the transformer to its maximum, without overloading it, the primary will be 4.16 amps at 240 volts and the secondary will be 8.33 at 120 volts. <<>> voltage times amps equals wattage
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
depends on the type of transformer, does it have any markings? just type them into google or look for a capital a 'A' for amps or mA for mili amps.
what is the fault in the transformer, it trips when it is charged.it is charged through the 100 amps MCCB.
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
On a 1kva you have 1000 watts capacity. To fine the current the formula is I = W/E. The secondary side of the transformer has the capacity of 1000/120 = 8.3 amps. In your question you do not put the amps across the secondary you draw amps from it. Using the transformer to its maximum, without overloading it, the primary will be 4.16 amps at 240 volts and the secondary will be 8.33 at 120 volts. <<>> voltage times amps equals wattage
The transformer itself does not pull current. Whatever you connect to the transformer pulls current. Whatever the output voltage of the transformer is, divide that into 600 and you get maximum current possible without burning up the transformer. At 24V that's 25 amps.
2.083 amps
The purpose of a transformer is to transform one voltage to another voltage. This can be in the configuration of stepping up the voltage or stepping down the voltage . The load is what establishes what the current from the transformer is going to be.
To answer this question a voltage must be given.
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
Find the wire from the secondary of the transformer. If it's a step-down transformer the thicker wire is the secondary. Measure its diameter in inches and calculate its cross-section area in square inches. The current rating for transformer wire is 1000 amps per square inch, or 1.55 amps per square mm.
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
If the load you are connecting to the transformer uses 1.5 amps or less, yes.