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How many feet are traveled in a car going from 0-60 mph in 6.8 seconds Starting from rest and assuming the rate of acceleration is constant?
Wiki User
∙ 11y ago
Acceleration is change of speed per unit of time Our car's change of speed is 60-0 = 60 mph Aceeleration is 60*3600/5.4 miles/hour squared = 40000 miles/hour squared Alternatively: 60 mph = 88 feet/sec Change of speed = 88-0 feet/sec Acceleration = 88/5.4 = 16.30 ft/sec sq.
Wiki User
∙ 15y ago
Wiki User
∙ 14y agoTo solve this, you can use the following constant acceleration equation:
Δx = vit + 1/2at2
where Δx is the change in position, vi is the initial velocity, t is the time interval, and a is the acceleration.
To solve, simply plug in the given values.
Δx = (4.0 m/s)(5.0s) + 1/2(3.5 m/s2)(5.0s)2
Δx = 64 m
Wiki User
∙ 11y agos = v(o)t + 0.5 at2 ... a = (v(f)- v(o)) /t .... v(o) = 0
v(f) = 60 miles/hr x 3600 s / 5280 ft = 450/11 ft/sec
a = (450/11)/6.8 =6.016 ft/sec2
s = 0x6.8 + 0.5x(6.016)x(6.8)2 = 139.1 feet
Wiki User
∙ 13y agoAverage speed during the 4 seconds = 1/2 (0 + 60) = 30 mph
Distance traveled = (average speed) x (time) =
(30 mi/hr) x (4 seconds) x (5,280 ft/mi)/(3,600 sec/hr) = 176 feet
Wiki User
∙ 15y agoThat's about 35 mph. That's pretty poor. Any decent car can to 60mph in about 9 or 10 seconds.
Wiki User
∙ 15y ago8
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