How many grams of KCl are needed to make 100 ml of a 3.5M solution?

Answer 1

In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg

Answer 2

298g KCl

molarity = moles of solute

Liters of solution

1.00M = x mol

4.00 L

4 mol KCl is 298g KCl (molar mass = 74.5g)

Answer 3

dissolve 26.075g KCL and make final volume 100ml. The final product will be 3.5M solution of Kcl