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A 0.205 M solution will have 0.205 moles per liter. 250 milliliters is 1/4 of a liter, so in that sample, there will be 0.05125 moles. NaOH has a molar mass of 39.9971 grams per mole, so 2.05 grams added to 250 mL of water will make the desired solution.

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9y ago
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15y ago

1 molar NaOH contains 40 grams of NaOH per every liter of water

so 2 M NaOH contains twice that amount, ie. 80 grams per liter. Then, ine 250 ml of weater, there should be 80/4 = 20 grams of solid NaOH dissolved.

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13y ago

Use liters to match other units. So. 100 ml = 0.1 liters

Molarity = moles of solute/ volume ( liters in this case ) of solution

1 M NaCl = moles NaCl/0.1 liters

= 0.1 moles NaCl (58.44 grams/1 mole NaCl)

= 5.844 grams of NaCl needed to make solution.

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13y ago

Can find moles this way.

Molarity = moles of solute/Liters of solution

( 500 ml = 0.500 Liters )

1 M NaOH = moles NaOH/0.500 Liters

= 0.5 moles NaOH (39.998 grams/1 mole NaOH)

= 19.999 grams NaOH needed ( call it 20 grams )

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11y ago

0.5 M NaOH stands for 0.5 mol per liter of NaOH in an (aqueous) solution.

The aim is to get 1/4 of a liter of this molarity i.e. one needs

1/4 l * 0.5 mol/l = 0.125 mole

One mole of NaOH weighs 40 grams so 0.125 moles weigh 0.125 * 40 g = 5 g

The preparation is as follows:

Weigh 5 grams NaOH, put them in the volumetric flask, add water until reaching the 250 ml mark.

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10y ago

25ml of NaOH then use the density convert that into grams

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14y ago

mol = vol x conc

mol = 0.1 x 1

mol of NaOH = 0.1

mol = mass/Mr Mr of NaOH = 40

0.1 x 40 = 4g

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8y ago

The answer is 20 mL.

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12y ago

4 grams

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12y ago

4.98 grams

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Q: How much 2.5 M NaOH is necessary to create 500 ml of 0.100 M NaOH?
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