A 0.205 M solution will have 0.205 moles per liter. 250 milliliters is 1/4 of a liter, so in that sample, there will be 0.05125 moles. NaOH has a molar mass of 39.9971 grams per mole, so 2.05 grams added to 250 mL of water will make the desired solution.
1 molar NaOH contains 40 grams of NaOH per every liter of water
so 2 M NaOH contains twice that amount, ie. 80 grams per liter. Then, ine 250 ml of weater, there should be 80/4 = 20 grams of solid NaOH dissolved.
Use liters to match other units. So. 100 ml = 0.1 liters
Molarity = moles of solute/ volume ( liters in this case ) of solution
1 M NaCl = moles NaCl/0.1 liters
= 0.1 moles NaCl (58.44 grams/1 mole NaCl)
= 5.844 grams of NaCl needed to make solution.
Can find moles this way.
Molarity = moles of solute/Liters of solution
( 500 ml = 0.500 Liters )
1 M NaOH = moles NaOH/0.500 Liters
= 0.5 moles NaOH (39.998 grams/1 mole NaOH)
= 19.999 grams NaOH needed ( call it 20 grams )
0.5 M NaOH stands for 0.5 mol per liter of NaOH in an (aqueous) solution.
The aim is to get 1/4 of a liter of this molarity i.e. one needs
1/4 l * 0.5 mol/l = 0.125 mole
One mole of NaOH weighs 40 grams so 0.125 moles weigh 0.125 * 40 g = 5 g
The preparation is as follows:
Weigh 5 grams NaOH, put them in the volumetric flask, add water until reaching the 250 ml mark.
25ml of NaOH then use the density convert that into grams
mol = vol x conc
mol = 0.1 x 1
mol of NaOH = 0.1
mol = mass/Mr Mr of NaOH = 40
0.1 x 40 = 4g
The answer is 20 mL.
4 grams
4.98 grams
5 mL of NaOH
50% purity NAOH liquid . if the density is 1.53 . so one liter hou much NAOH is here ?
Molarity = moles of solute/volume of solution 0.53 M NaOH = moles NaOH/3.8 Liters = 2.014 moles, or about 80 grams
alot
First you must either know how much 50% NaOH you want to start with or know how much 2% NaOH you need at the end. Let's say you want 1L of the 2% NaOH. Use this equation, and solve for x, where in this case, x is the volume of 50% NaOH needed. (50% NaOH)x = (2%) * 1000 ml 0.5x = 0.02(1000) x = 20/0.5 = 40 Therefore, 40 ml of 50% NaOH in 960 ml water will produce 2% NaOH. Use a 1000 ml volumetric flask to be most precise.
5 mL of NaOH
You dont - adding NaOH increases pH.
50% purity NAOH liquid . if the density is 1.53 . so one liter hou much NAOH is here ?
Molarity = moles of solute/volume of solution 0.53 M NaOH = moles NaOH/3.8 Liters = 2.014 moles, or about 80 grams
alot
r=500
First you must either know how much 50% NaOH you want to start with or know how much 2% NaOH you need at the end. Let's say you want 1L of the 2% NaOH. Use this equation, and solve for x, where in this case, x is the volume of 50% NaOH needed. (50% NaOH)x = (2%) * 1000 ml 0.5x = 0.02(1000) x = 20/0.5 = 40 Therefore, 40 ml of 50% NaOH in 960 ml water will produce 2% NaOH. Use a 1000 ml volumetric flask to be most precise.
Molarity = moles of solute/volume of solution so, 29.4 grams sounds about right.
a pH=10 solution of NaOH should contain 0,0001 moles of NaOH/liter. (1 mole/liter for pH=14, 0,1 for pH=13, etc.) A mole of NaOH is 40g-s. (Na=23g O=16g H=1g) 0,0001 mole is 0,004gs. You need the amount necessary for a quarter of a liter, so you divide by four. The result is that you need 0,001gs of NaOH. So if you need to make that solution without any precise laboratory equipment, you should make much larger quantities and just measure 0,250 l-s.
-1602 kJ
20.6
The amount of NaOH needed to raise the pH from 8 to 10 depends heavily on the conditions. The amount of NaOH needed will increase as the volume of the solution increases. Even more importantly, buffers can stabilize the pH significantly. If buffers are presently, the pH change will be much more gradual, and more NaOH will be required.