answersLogoWhite

0


Best Answer

This is a mass stoichiometry problem. Start with the balanced equation:

CaCO3 --> CaO + CO2.

Do a conversion from 50g CaO to moles:

56g/1mol=50g/x, x=.9 moles.

The equation is balanced as written, with all coefficients understood to be 1.

So: .9 moles CaO means .9 moles CaCO3.

Do another conversion from moles to grams:

100g/1mol=x/.9 moles.

Solve for x to get 90 grams.

(56g=molar mass of calcium oxide; 100g=molar mass of calcium carbonate.)

User Avatar

Wiki User

11y ago
This answer is:
User Avatar
More answers
User Avatar

Fabian Valles

Lvl 2
2y ago

10

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many grams of calcium carbonate are required to prepare 50.0 g of calcium oxide?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many grams are in 2.8 moles of calcium carbonate?

2,8 moles of calcium carbonate have 240,208 g.


How many grams of calcium oxide will remain after 12.25grams of calcium carbonate is completely decomposed?

6,863 grams of CaO


How much calcium carbonate in grams can be dissolved by 5.00 grams of hydrochloric acid?

5


What mass of calcium oxide is produced by heating 25 moles of calcium carbonate?

1400 grams


How many ions of calcium present in 40 grams of calcium carbonate?

9.03x10 23 ions


How many grams of calcium in 418 grams of Ca CO 3?

Calcium has Wt 40, carbon is 12 and oxygen 16, so the MWt of calcium carbonate is 40+12+3x16=100. As this contains 40 calcium, calcium carbonate is 40% calcium. 40% of 418 is 167.2grams


If a balanced equation of calcium chloride dihydrate and sodium carbonate with the calcium chloride dihydrate is 1.0g what would the weighed measurement be of sodium carbonate?

0.720940834 grams


How may grams of calcium carbonate will be needed to form 4.29 liters of carbon dioxide?

The answer is 19,288 g cacium carbonate.


How many moles of calcium carbonate are in 1.719 grams?

Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.


How many moles are there in 200 grams of Calcium Carbonate?

For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.


How many ions of carbonate present in 40 grams of calcium carbonate?

caco3 (40)+(12)+3(16) =100/40 =2.5


How many grams of calcium carbonate are needed to produce 45.0L of carbon dioxide at STP?

201