Theoretically 22 kW is equivalent to 29.5 HP but there are some power losses in the motor and the probable maximum output of mechanical power is 25 HP.
I would go with 20 amp 3 pole 15 amp will also do
Depends on the motor and the load on that motor. If the motor is loaded to its capacity, it will draw the same amount of power as it would on 690 volts - which will result in ( 690/480 = ) 144% of normal current, which will thermally damage the motor, or will trip overload protection.
It is probably a three phase 50 Hz motor.
depends what the source voltage isone horsepower equals to 746watts (assuming 100% efficiency)746 watts divided by voltage source equals current (amps)AnswerIn countries, such as the USA, where the horsepower is still used as a means of measuring power, it is always used to measure the output power of a motor.So, in order to determine the current drawn by the motor, you will first need to find out its input power. The input power is the output power divided by the machine's efficiency. Once you know its input power, then you can find its current by dividing the input power by the supply voltage. In practise, you will need to use a wattmeter to determine its input power.
Yes, if the motor is rated 240 volts 3 phase.There is such a thing as 240 volt 3 phase power.However if you are asking if you can use 240 volts single phase on a three phase motor, then the answer is no.
to calculate: 1hp=745W 3hp=745*3=2.2Kw assuming a 3 phase motor power is V*I*pf*the square root of 3 I would gues a PF of 0.8 if its a resonable motor which gives about 7.2 amps per phase. if the PF is bad say .65 it could pull up to 9 amps in short, too little information to give you the actual answer.
The formula you are looking for is, kW x 1000/1.73 x volts x pf (power factor).
If the motor is a three phase the most likely voltage the motor operates on will be 480 volts.
form_title=Well Pump Installation form_header=12353 Are you in need of single or three phase power?*= () Single phase () Three phase () Don't Know Do you know the voltage of you power supply?*= () 155 volts () 208 volts () 230 volts () 460 volts () Don't Know () Other
There will be a significant reduction in the mechanical power output available from the motor.
3.7 kwh
To answer your question properly, you need to know the input power to these machines, whereas you are specifying their output powers. In other words, you really need to know their efficiencies in order to determine their input powers.Once you have figured out their input powers, then you need to divide the power by the supply voltage in the case of the single-phase motor, and the power divided by 1.732 times the supply voltage in the case of the three-phase motor.Incidentally, your motors' specs should either be 230/400 V or 240/415 V, NOT 230/415 V.