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The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.

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Douglas Powlowski

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14y ago

The 8086/8088 does not have 1 MB memory, rather, it can address 1MB memory. The processor has a 20 bit address bus. With that, it can select among 220 distinct addresses, or 1,048,576 addresses. That is 1 MB of memory.

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11y ago

since 8086 has 20-bit address line

therefore 2^20=1048576 bytes=1048 KB=1MB

Hence Addressing up to 1MB memory

vivek Lunkar

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The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.

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Q: How many address lines are required to access 1MB RAM using microprocessor 8086?
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Related questions

How many Address lines and data lines of microprocessor and microcontroller?

Microprocessor has 16 address lines and microcontroller has 20 address lines


How many address lines are needed to access 256KB of main memory?

The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.


Why all the 16 address lines are not act as a data lines in 8085 microprocessor?

the 8085 microprocessor is a 8-bit microprocessor and these are bidirectional but the address lines are unidirectional.these address lines are used to address the location of the instruction in memory .these data lines are used to transfer data between processor and peripheral devices. when the address of the instruction will be recognized by the address lines the data will be send to the processor therefore the 16 address lines are not act as a data lines in 8085


A microprocessor with 12 address lines is capable of addressing?

A microprocessor with 12 address lines is capable of addressing 4096 locations in memory. The Intel 4004 and the DEC PDP-8 are examples of processors with 12 address lines.


How many address lines are required if micro processor has to access 2kb memory?

2kb=2*1024=2048 2^11=2048 therefore 11 address lines are required


What is segment in microprocessor?

segment is for converting physical address to logical address , here on taking 8086 microprocessor as example, we have 20 address lines but it is capable of taking only 16 address lines.... so to convert that 20 into 16 segment is used....


How many address lines would be required for a 2K?

In the 2k*16 , the 11 address lines are required and the 16 input-output lines are required..


What is the basic construction of microprocessor?

1)address lines to refer to the address of a block 2)data lines for data transfer 3)IC chips 4 processing data


How many memory location can be address by microprocessor with 14 address line?

You can address 214 or 16384 different locations with 14 address lines.


What are the basics of microprocessor?

1)address lines to refer to the address of a block 2)data lines for data transfer 3)IC chips 4 processing data


How many Address line of 8085 microprocessor?

There are 20 address lines and 16 data lines in the 8086 microprocessor. The low order 16 address lines are multiplexed with the data lines. Some of the high order address lines are multiplexed with status lines.


How do you calculate number of address lines needeed for 1 MB?

20 address lines are required