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One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.
So you multiply 4.2 with 6.02 × 1023 to get 2.53 × 1024
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∙ 13y ago
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∙ 12y agoA formula unit for aluminum is a single atom, while a molecule of aluminum oxide has the formula Al2O3. Therefore, one mole of aluminum provides enough aluminum atoms for only one-half mole of aluminum oxide.
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∙ 10y agoThe chemical formula for aluminium oxide is Al2O3. In each formula unit of Al2O3, there are three O atoms. Thus in 3 moles of Al2O3 there would be 9 moles of O atoms.
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∙ 12y agoThere are two moles of Al3+ ions (and three moles of O2-) in one mole Al2O3 .
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∙ 7y agoWe need 1,08 moles oxygen.
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∙ 14y ago5.05
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∙ 16y ago6.8
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∙ 12y ago7.4 moles
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How many moles og Al are in 2.16 mol of Al2O3?
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
What is the theoretical yield of aluminum oxide if 2.40 mole of aluminum metal is exposed to 2.10 mol of oxygen?
Balanced equation: 4Al(s) + 3O2(g) ==> 2Al2O3(s)2.40 mol Al ==> 1.2 moles Al2O3 (mole ratio of Al2O3 : Al is 2:4 or 1:2)2.10 mol O2 ==> 1.4 moles Al2O3 (mole ratio of Al2O3:O2 is 2:3)Therefore, Al is the limiting reactant.Theoretical yield will thus be 1.2 moles Al2O3. If you need mass, it is 1.2 moles x 102 g/mol = 122 g
An ionic compound is made entirely of aluminum and oxygen what is the formula for this compound?
Al+3 O-2 ---------> these are the ions with their chargesAl2O3 -------------> this is when they are bonded together Al2O3
How many molecules does alcl3 dissociate into?
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.
How many moles og Al are in 2.16 mol of Al2O3?
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
What is the percent yield of this reaction if 750.0 g of aluminum oxide produced 256.734 g of aluminum?
Aluminum oxide, Al2O3 would produce aluminum by the following decomposition:2Al2O3 ==> 4Al + 3O2 750.0 g Al2O3 x 1 mole/101.96 g = 7.356 moles Al2O3 Theoretical yield of Al = 7.356 moles Al2O3 x 4 moles Al/2 mole Al2O3 = 14.71 moles Al Theoretical mass of Al = 14.71 moles Al x 26.98 g/mole = 396.9 g Al Percent yield = 256.734 g/396.9 g (x100%) = 64.68% yield (to 4 significant figures)
In the reaction of aluminum metal and oxygen gas aluminum oxide is formed How many moles of O2 will react with 2.0 moles Al?
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.
What is the theoretical yield of aluminum oxide if 2.40 mole of aluminum metal is exposed to 2.10 mol of oxygen?
Balanced equation: 4Al(s) + 3O2(g) ==> 2Al2O3(s)2.40 mol Al ==> 1.2 moles Al2O3 (mole ratio of Al2O3 : Al is 2:4 or 1:2)2.10 mol O2 ==> 1.4 moles Al2O3 (mole ratio of Al2O3:O2 is 2:3)Therefore, Al is the limiting reactant.Theoretical yield will thus be 1.2 moles Al2O3. If you need mass, it is 1.2 moles x 102 g/mol = 122 g
An ionic compound is made entirely of aluminum and oxygen what is the formula for this compound?
Al+3 O-2 ---------> these are the ions with their chargesAl2O3 -------------> this is when they are bonded together Al2O3
What is the theoretical yield of aluminum oxide if 2.60 mol of aluminum metal is exposed to 2.25 mol of oxygen?
the answer is 4.7 1] Figure out how many moles of Al and O2 2.5g is. 2] Compare the ratio of the moles from A to the 2:3 ratio in Al2O3; do you have more Al proportionately than O2 or vice versa ? This is called 'finding which reagent is limiting".... 3] Take whichever reagent was limiting and find out how many moles of Al2O3 you can get from it. THen find the mass.
How many molecules does alcl3 dissociate into?
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.
How do you calculate moles of ions in 0.200 moles aluminum perchlorate.?
0,6 moles of (ClO4)3- and 0,2 mol Al
How many grams of aluminum oxide is formed when 6.4 grams of aluminum is reacted?
To answer this first of all you need to know the equation of the reaction. 4Al + 3O2 ----> 2Al2O3 Then you need to know how many moles of aluminium you have mass = moles x molecular weight, therefore: moles = mass/ molecular weight. 38.8/21 = 1.85 (with rounding). This is the number of moles of aluminium you have. To work out how much oxygen is added you need to take the ratio of moles(O2:Al) from the equation (3/4 or 0.75) and multiply by the number of moles of aluminium 1.85 x 0.75 = (5.55/4). This is the number of moles of oxygen. I left it like this as it will be nicer to multiply out later. As you want the final mass you need to find the mass of oxygen added to the aluminium using mass = moles x molecular weight from before except as there are two oxygen atoms per molecule so the number needs to be doubled. (5.55/4) x (16 x 2) = 44.4g. This how much oxygen is added in the creation of aluminium oxide. To get the final total you add the amount of aluminium to the amount of oxygen added 38.8g + 44.4g = 83.2g
How many moles of aluminum oxide can be made if 4.0 moles Al completely react?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
How many moles of aluminum oxide can be made if 5.23 moles Al completely react?
This is a mole stoichiometry problem. Start with the balanced equation for the synthesis of aluminum oxide: 4Al + 3O2 --> 2Al2O3. The ratio of aluminum to aluminum oxide in this equation is 4:2, or 2:1, so 5.23 moles Al means half that number for Al2O3, so about 2.62 moles of aluminum oxide will be produced.
