Only one.
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It takes 3 non collinear points to define one specific circle. With only two points an infinite number of circles can be drawn. Proof: Given two points A, B draw the line between them. Then find the perpendicular bisector of the line AB. Any point on the perpendicular bisector is equidistant from the two original points, A and B. A circle with center C and radius AC will then pass through points A and B. There are infinite point C's on the perpendicular bisector so there are infinite circles. Given three points A, B and D you can find the perpendicular bisector for line segements AB and then the perpendicular bisector fof line segment BC. The two perpedicular bisectors will not be parallel because the points A, B and D are non collinear. This means the two perpeniducar bisectors will intercept at only one point C(like any two intercepting lines). This point C is equidistant from points A, B, and D. A circle with center C and radius AC will then pass through all three of the points. Since there is only one point C that lies on both perpendicular bisectors, there is only one circle possible.
A line segment has exactly two endpoints. If it had less, then it would just be a point. If it was more, then it wouldn't be a segment anymore.
There are infinitely many lines perpendicular to this line. All of them have the slope of -4/3, if that fact is of any help to you.
Each of the eight line segments is perpendicular to 2 line segments. So there are 8 pair in all.
Exactly one. No more, no less.
Since there is no such word as "perpindicuar", it is difficult to be sure. A line segment can have only one perpendicular bisector.
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All bisectors intersect the line segment at the midpoint. There can be multiple bisectors, intersecting at the midpoint at different angles, but they all intersect the line segment at its midpoint. The midpoint separates the line segment into two equal halves.
A bisector is a line (or line segment) which passes through the midpoint. You can have multiple lines intersect at this one point, and all of them will bisect the original line segment, since they pass through its midpoint. A perpendicular bisector passes through the midpoint, and also is perpendicular to the original line segment, so there will be only one of those.
Equilateral triangles have 3 perpendicular bisectors
Explain why a line segment can have one midpoint but many bisectors
no-- It only has one. Since it is a segment, it has a definite start and end, so it has only one middle (the bisector).
Infinitely many. Each line segment contains one point which bisects it. Any one of the infinite lines through that point, apart from the original line, is a bisector.
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