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How many times will the number 5 show up if a fair number cube rolled 300 times?
If the cube faces are numbered 1 through 6 then 5 will show up once every six times, so 300 rolls will show up a 5 about 50 times based on probability
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\ntwo out of six or one out of three
A fair die is rolled nine times What is the probability that an odd number 1 3 or 5 will occur less than 3 times?
i dont know what the anser is sorry
the chances of rolling a 2 each time during 1 set of 3 rolls is -1 in 216- sets.. i believe the formula is:. 1 in 6 - the chance of rolling a"2". then multiply the chances …for each separate roll 1/6 x 1/6 x 1/6 = 1/216
A fair cube with faces 6 4 3 7 9 and 2 is rolled four times What is the probability that all rolls will result in an even number?
A six sided cube numbered 1 through 6 is rolled 120 timesThe number 4 comes up 19 times what is the theoretical probability of rolling a 4?
Because we are only modeling one event, all six outcomes of the die are equally possible. The probability of rolling a four (or, for that matter, any number) is 1/6, or .16666…6 repeating. Now, since we are modeling 120 rolls, the theoretical number of outcomes of four (or, again, any number) is 1/6 * 120 = 20 outcomes. The second sentence of the problem is unnecessary.
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be …lost on you. . If a number cube (die) contains the numbers 1, 2, 3, 4, 5, and 6, and the cube is fair, then the probability of rolling a 2 is 1 in 6. If you roll the cube 100 times, you would expect to get 2's 100 / 6, or 17 times. However, 100 trials is not a lot of trials, so the experimental outcome might not match the theoretical probability.
Assuming the die is fair, the probability of a number greater than three is a half so the EXPECTATION would be that it will land on a number greater than 3 thirty times. But, …this is the expectation; the actual number could be anything from 0 to 60.
Never. If you roll it 1 time, there can be no "then".
Type your answer here... 15
Each time you have a probability of 1/6; therefore, your expectation is 100/6 = 16.67. You will get around 16 or 17 ones, but the actual results will obviously vary - you can …get more or less than that, too.. \n
1/6 of all outcomes should be a 5. 300*1/6=50 This is the answer regardless of what you are rolling for. Youwould find whatever number you want and average about 50 times ifyo…u were to roll the dice 300 times. You might not get exactly 50,but it won't be far from that. There are faces on a die, and theodds of any one of those 6 numbers showing up is 1 out of 6 times. The above is only true if the dice are not rigged in any way("loaded dice"). Now, if only one number likes to keep coming up,you might be dealing with loaded dice. In that case, the dice aremade for cheating and the mathematical laws of average no longerapply.
Probability = number_of_ways_of_success / total_number_if_outcomes As a cube has 6 faces and you have only specified that it has fivenumbers (1-5), one of those numbers must …be repeated, thus theprobability of rolling a 5 depends upon whether there is one or twosides bearing a 5: If there is only 1 side bearing a 5, then it is 1/6 If there are 2 sides bearing a 5, then it is 2/6 = 1/3 If you meant a five sided solid, then there is no such regularsolid and some face(s) would be biased to appear and it woulddepend upon which face has the 5. However, an icosahedron has 20 faces and the numbers 1-5 could berepeated 4 times each, meaning that the probability of rolling a 5would be 4/20 = 1/5. If you had a regular pentagonal spinner, with each digitcorresponding to an edge, then the probability of spinning a 5would be 1/5. If you mean a standard die: a cube with six sides numbers 1-6 (andthe 1-5 was a typographical error), then the probability is 1/6.
What is the probability that if 2 fair value cubes are numbered 1 - 6 are tossed at the same time would show the same number?
The probability is 6/36 = 1/6.
What are the odds against fair value cubes numbered 1-6 tossed at the same time showing the same number?
The odds of this happening are 6/36 = 1/6 ~= 0.1667