15! - 2! x 14!
= 1133317785600 ways
first we have to place 14 boys leaving one talkative boy. so 14! for placing the 14 boys. now we have 15 places vacant to place the 2nd talkative boy .but as 1st talkative boy is already placed places adjacent to him are not to be used so 13 places left. answer is 14!*13.
Yes. You'll need 26 tables.
have a frined to help u out {in the mean time I believe the answer is that five students can be seated 120 different ways and still be "in circle" as you requested.} Shift+]
The answer is 4!*24 = 24*16 = 384 ways.
62
It depends upon how many students are talkative. I'll give you two examples. 0 students talkative - 1 way 1 student talkative - 15 ways
first we have to place 14 boys leaving one talkative boy. so 14! for placing the 14 boys. now we have 15 places vacant to place the 2nd talkative boy .but as 1st talkative boy is already placed places adjacent to him are not to be used so 13 places left. answer is 14!*13.
Is it 12
Usually the plan is for the students to be seated and organized so that they arrive at the podium in alphabetical order, by last name. or they seat them by how pretty they are
if in a class pupil 47 is opposite pupil 16 when the group is seated in a circle how many students are in the PE class?
because that will equal 22 nice even rows of 6 students
Yes. You'll need 26 tables.
The rhythm probably calms them.
have a frined to help u out {in the mean time I believe the answer is that five students can be seated 120 different ways and still be "in circle" as you requested.} Shift+]
The answer is 4!*24 = 24*16 = 384 ways.
students can be seated in 16 diffrent ways. multiply or draw a table. * * * * * Unfortunately, that is an incorrect answer. The correct answer is 4*3*2*1 = 24 ways. For the first seat, on the left, you can pick any one of the 4 students. For the next seat, you have only three students so you have 3 choices. So the number of ways of filling the first two seats is 4*3. Continue the process.
21 in each section