V= Q/A (velocity = volumetric flow rate / area)
conversion: 1000L = 1m3; therefore 1900L/min= 1.9m3/min
V = (1.9m3/min * 1min/60s) / Pi*(.02m)2/4 = 100.798 m/s
Simplified Bernoulli Equation:
∆P/rho + 0.5*(initial velocity2-final velocity2) = 0 (rho=density)
(equation assumes no fluid height changes and no frictional losses)
∆P/(1000 kg/m3) + 0.5*(02 - (100.798 m/s)2) = 0
∆P = 5.08x106 N/m2= 5.08x106 Pascals
P= F/A (Pressure= Force/Area)
F= P*A
F= ∆P * Area = 5.08x106 * Pi*(.02m)2/4 = 1595.97N
A height of nozzle was not given; however, there is a minimum height when you specify a horizontal distance of 50m.
Minimum nozzle height above ground to reach 50 meters horizontal distance:
d=r*t (distance= rate * time)
t= d / r
t= 50m / 100.798m/s = 0.496s
(time for a droplet to leave the nozzle and travel 50m horizontally)
h= g*t2
(height of a falling object = gravity * time2 assuming spray nozzle is horizontal)
h= 9.81m/s2 * (0.496s)2 = 2.41m above grade
The minimum height will change if the nozzle is angled up or down.
Note: 9.81m/s2 is approximately the earth's gravitational acceleration at sea level at the equator.
A cubic meter is a unit of volume, specifically 1,000 litres.Litres per minute is a unit of flow.Units of volume and units of flow do not correlate without some factor of time. The question is invalid. Please restate the question.
90 minute doors are required when building code requires a 90 minute or 2 hour assembly rating. For example, with IBC '06, 715.4, if a 2 hour wall is required, you can have a 90 minute door. The fire resistance rating depends on the type of building occupancy and component. For example, for fire barrier assemblies or horizontal assemblies, for occupancy of type A (Assembly), B (Business), E, F-2, H-4, H-5, I, M (Merchantile), R, S-2, the fire rating is 2 hours. For other types, say U (Utility) the rating is 1 hour and for H-1 and H-2 (High Hazard) its 4 hours. Since the issue is complex, consult an architect to determine a specific application.
What is the force required in N? Work in J? Power Required in W? A vacuum in the evaporator of a refrigerating system is 284 mmHg. The barametric pressure is 742 mmHg. Determine the absolute pressure in Pa. pHg= 13596 kg/m^3. Mass of 210 kg is elevated 24.5m in 1 minute 34 seconds.
Since current in amperes is defined as one coulomb per second, then passing one coulomb through a conductor in one minute consitututes a current of one sixtieth of an ampere, or 16 2/3 milliamperes.
One minute of arc as measured at the centre of the Earth covers one nautical mile on the surface of the Earth at mean sea level. One nautical mile is 6080 feet or 1853.2 metres. Therefore one second of arc would be 6080 / 60 = 101.3 feet or 30.886 metres. Lines of latitude are at regular intervals parallel to the equator. The relationship between degrees of latitude and the distance spanned on the earths surface remains constant. Therefore at all latitudes 1 minute of latitude spans 1 nautical mile on the earths surface. Lines of longitude converge at the poles. Therefore the relationship between degrees of longitude and the distance spanned on the earths surface is reduced as the poles are approached. At the equator the distance spanned by 1 minute of longitude would be 1 nautical mile. At the poles it would be zero. To calculate the actual distance on the surface of the earth between two points of known latitude and longitude requires a knowledge of spherical trigonometry to calculate the great circle distance between the two points. The distances quoted are for the surface of the earth at mean sea level. Distances will be increased above sea level and reduced below it.
Fifty
Cubic feet per minute x 28.3168 = liters per minute
96 gallons per minute = about 363.4 liters per minute.
Multiply liters per minute by 0.0353146667 to get cubic feet per minute.
24.72 cubic feet per minute at 700 liters per minute.
5 liters per minute equates to 0.005 cubic meters per minute.
4 liters per 25 seconds = 9.6 liters/minute
Multiply the number of Liters/minute by 0.06
60 seconds in a minute, so multiply by 60.
milliliters per second x 0.06 = liters per minute 12mL/s x 0.06 = 0.72 liters per minute
Since a cubic meter is the same as 1000 liters, you have to divide the liters by 1000.
It depends on the flow rate which, in turn, will depend on the pressure.