The heat capacity of water is approximately 1 cal/g/°C or 1 kcal/kg/°C.
The boiling point of water is 100 °C so taking it from 20 °C boiling point means taking it to 100 °C - a change of 80 °C.
The indicated change would require adding about 80 kcal of energy.
From steam tables. the enthalpy of liquid water at 20 °C is 20.05 kcal/kg and the enthalpy at 100 °C is 100.09 kcal/kg - for a change of 80.04 kcal/kg or 80 kcal for 1.0 kg of water (taking into account that the original problem statement only provided values to 2 significant digits.)
You need:
Q= 4.18(Kj/kg.C) x 1 (Kg) x (98-20) = 326 Kj = 78 calories.
Specific heat capacity water - 4.187 kJ/kgK
4.187 kJ/kgK * 10'K * 1Kg = 41.87 Kj
How much heat must be added to 1.0 kg of water at 0 degrees Celsius to convert it into 1.0 kg of water at 100 degrees Celsius?
It is 416.666... kilojoules.
Minus 33.34 degrees Celsius
about 100 degrees Celsius
The boiling point for water is 212 degrees Fahrenheit, or 100 degrees Celsius, or 373 kelvin
100 degrees Celsius is 212 degrees Fahrenheit. This is the boiling point of water at sea level.
Water does not have a specific temperature. Its freezing point is 0 degrees Celcius and its boiling point in Celcius is 100 degrees.
In Celsius, it is 100 degrees.
The Boiling Point Temperature is 212 degrees Fahrenheit and 100 degrees Celsius
100 degrees celsius
the boiling temperature of water
Different substances have different boiling temperatures.
Minus 33.34 degrees Celsius
about 100 degrees Celsius
100 degrees Celsius or Centigrade 212 degrees Fahrenheit
The Celsius temperature scale is referenced to the water's freezing temperature (0 degrees) and the water's boiling temperature (100 degrees at sea level).
It is the temperature of boiling, just in degrees Celsius.
100 degrees celsius
100 Degrees Celsius