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Need voltage for the motor. Then use I = W/E. __________________________________________________________________-

Power = Current x Voltage, so Current = Power/Voltage . If the 1000 w motor is connected to a 110 V outlet it will draw 1000/110 = 9.1 amps. If its connected to a 220 V outlet it will draw half that.

---- For single phase calculations, HP = I x E X Eff X pf/746. Transpose for I. I = HP x 746/E x Eff x pf. To calculate HP 1000/746 = 1.34, I = 1.34 x 746/110 x .9 x .9 = 11.2 amps. This is on the assumption that the motor is 90% efficiency and is using a 90% power factor.

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15y ago
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13y ago

If the "kilowatt" is something the motor uses whenever it's running, then the

same unit can't measure something that gets tallied up over time.

The kilowatt is the unit of power. Power is the rate at which energy is used.

The motor uses energy at the rate of 1.1 kilowatts.

You're asking for the amount of energy the motor uses in one hour. The unit

you want is the "kilowatt-hour". That's the total amount of energy used by

something that uses it for an hour at the rate of 1 kilowatt.

Your motor uses energy at the rate of 1.1 kilowatts. If it does that for an hour,

then it uses a total of 1.1 kilowatt-hours of energy.

If it runs for 2 hours, then it uses 2.2 kilowatt-hours of energy. If it only runs

for 1/2 hour, then it uses only 0.55 kilowatt hours of energy.

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12y ago

To answer this question, you need to know (1) the efficiency of the machine at full load (2 kW is its output power, and it's necessary to know its input power), and (2) the voltage at which the motor is operating. Incidentally the symbol for kilowatt is 'kW', not 'kw'.

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10y ago

Under full load 1.5 Kilowatts an hour. That is why it is called a 1.5Kw motor!

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