0
If you are a normal household, this will be standardised by your local council/municipality. They base this on the Demographics of that particular society considering the ff: (income, spending power, lifestyles, culture, etc). Generally, for home-owners using electrical power just for lighting and media, and maybe occassional electric plate stove, 20A meters will suffice. However, when one considers using geysers, full-electric-stoves, high powered equipment, then 60A will be applicable, which is what is used generally in urban households. Basically, all depends on what you need to use this power on, check all your appliances not forgetting your lights.
Wiki User
∙ 16y ago
Add your answer:
Earn +20 pts
How much solar power is required to completely power a home approx 1000kwh?
well im not sure but i no that the average home is powered with about 110 bolts but im not sure about solar energy or kwh. i hope that helps.
How much power is required for a ten story building?
12 of them
How much steam is required to produce 5 MW power in steam turbine?
How much steam is required to produce 5 MW power in steam turbine?In fully condensing turbine we will need 20 TPH steam required to generate for 5MW
How much watts battery power required for the 4 desktop computer?
123mb
How much coal is required for 1 mw power plant?
3.5 tonns of coal is required for producing 1 mw
How much electrical power is required to run this steam cleaner?
This steam cleaner does not use any electrical power.
How much psi is required to power bleed the brake system on an evo x?
10psi
How much DRAM is required for optimal performance by Windows Vista Home Premium?
1Gb
How many car batteries do you need to power your 100 amp home?
You cannot power a home with car batteries. Batteries are DC voltage. Your home operates on AC voltage. You could use a converter but the number of batteries required to operate an average home would be enormous.
It takes 200 N a box 10 meters in 8 seconds how much power is required?
First mulitiply Newton x meter to get the energy (or work) required. Then divide the result by the time to get the power.
How much power is required to do 40 J of work on an object in 5 seconds?
Power = (energy used) / (time to use that much energy) = 40/5 = 8 watts
A receiver requires 10nW as input power if all the system losses add up to 50dB then how much power is required from the source?
here, the power required by the receiver is the output power and that required from the source is input power. Gain in dB=10 log(output power/input power) we have, loss in dB = -gain in dB = 10 log(input power/output power) or, 50 = 10 log(input power/10nW) or, anti-log(5) = input power/10 nW so the power required from the source is antilog(5)*10nW = 1 mW
