The answer to this question depends on what method you are supposed to use. If a, b, and c are sides of a triangle, use the Pythagorean Theorem: C^2 = A^2 + B^2, C^2 = 25+49, C^2 = 74, C = 74^1/2 (or the square root of 74).
If you are following a pattern and A = 5, B = 7, then C may = 9.
It all depends on the context of the question.
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18
ac is 7 if b is 3 and a is 2 a nd c is 5
4
The -7 is called the difference. In any subtraction problem: a = b - c a is the difference b and c are terms (technically, b is minuend and c is subtrahend, but these terms are not really used in modern math)
the answer is a
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18
ac is 7 if b is 3 and a is 2 a nd c is 5
4
Z if d is equally to f plus10
The -7 is called the difference. In any subtraction problem: a = b - c a is the difference b and c are terms (technically, b is minuend and c is subtrahend, but these terms are not really used in modern math)
To find this: You know (B+C) = 7. Therefore you know (A+A )= 21 - (B+C). Therefore 21-7 = 14. So now you know (A+A) = 14. So you divide (A+A)/2. This equals 7. Therefore A = 7.
You haven't provided any choices for the "which of the following" part of your question. Such questions are best avoided here. However, assuming a, b and c are all natural numbers, all of the following are true for a<b AND b+c=10: a=1, b=2, c=8 a=1, b=3, c=7 a=1, b=4, c=6 a=1, b=5, c=5 a=1, b=6, c=4 a=1, b=7, c=3 a=1, b=8, c=2 a=1, b=9, c=1 a=2, b=3, c=7 a=2, b=4, c=6 a=2, b=5, c=5 a=2, b=6, c=4 a=2, b=7, c=3 a=2, b=8, c=2 a=2, b=9, c=1 a=3, b=4, c=6 a=3, b=5, c=5 a=3, b=6, c=4 a=3, b=7, c=3 a=3, b=8, c=2 a=3, b=9, c=1 a=4, b=5, c=5 a=4, b=6, c=4 a=4, b=7, c=3 a=4, b=8, c=2 a=4, b=9, c=1 a=5, b=6, c=4 a=5, b=7, c=3 a=5, b=8, c=2 a=5, b=9, c=1 a=6, b=7, c=3 a=6, b=8, c=2 a=6, b=9, c=1 a=7, b=8, c=2 a=7, b=9, c=1 a=8, b=9, c=1
6 + 12 - 5 = 13
a - b = c -(a - b) = -c b - a = -c
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)