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How much current flows through a 12 ohm flashlight bulb operating at 3.0 volts?
Wiki User
∙ 14y ago
Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.
Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.
Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.
Ohm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.
Wiki User
∙ 14y ago
Wiki User
∙ 13y agoUsing Ohms Law V/R=A
The Current would be .5 A
Wiki User
∙ 14y agoohm's law
V = IR
V = volts
I = Current
R = Resistance
3 = I *12
So I = 3/12
I = 0.25 Amp
Wiki User
∙ 13y agoAs we know that Ohm's law states that
V=IR
as in this question R=4 ohm and v= 3.0 V
=> 3=I*30
=>I=3/30
=>I=1/10 Ampere.
Wiki User
∙ 14y agoOhm's Law: Voltage = current x resistance; solving for voltage, current = voltage / resistance.
Wiki User
∙ 14y ago.25amps
Anonymous
0.5
Anonymous
A) 0.78
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