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In order to find the wind chill, one must follow the following formula: 35.74 + 0.6215T - 35.75(V0.16) + 0.4275T(V0.16) In this formula, "T" is the temperature in Fahrenheit, and V is the windspeed. Thus, the answer to the above question is -22.

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9y ago
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10y ago

above 10 °C 50 °F
-22º F

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11y ago

If the temperature is -5° Fahrenheit and the wind speed is 10 miles per hour the wind chill is -22.1F

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14y ago

on average 10 mph = 5 wind chill so about -10

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14y ago

-22 degrees F.

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14y ago

-22 degrees F.

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14y ago

-22 degrees F.

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14y ago

-22 degrees F.

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14y ago

-22 degrees F.

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Q: If the wind speed is 10 mph and the temp is -5 degrees Fahrenheit what is the wind chill?
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