Making the important assumption that each bulb is equal in electrical resistance, the current will increase proportionally to the number of bulbs added (until the current limit of the battery is reached, that is).
Clarification ...
The current through the bulbs that were already there doesn't change, but the
newcomer-bulbs add to the total current from the battery or power supply.
If you remove a light bulb from a parallel circuit, then the other bulb continues to shine because each light bulb is connected to its own pathway!
hi everyone my name is Daniel smith and i go to colmersschool rednal...
In accordance with Kirchhoff's Current Law, the supply current will be the sum of the branch currents. So, by adding an extra lamp, the supply current will increase by an amount equal to the current drawn by that lamp.
Yea if some one cud help me that would be great. =/
bulb don't be dim since in parallel current remain same
the other bulbs will continue to flow in parallel combination of circuit
As each parallel bulb is added the current will increase until the rated limit of the line is reached, causing the breaker to pop or the fuse to blow, reducing the current to zero suddenly.
Yes, of course. If the light bulb is connected, it takes energy from the circuit. IF it is taken away, it doesn't.
the bulbs would be very bright seeing as the two or more light bulbs have very easy excusable paths for electricity to flow and get to the light bulbAnswerBecause the voltage across each branch of a parallel circuit is the same, each lamp will be subject to its rated voltage and, therefore, will operate at its rated power output.
Electrical wiring for buildings is always done in parallel circuits.
The glass of the light bulb is not conductive, so the circuit would not be completed. You would need to join the wires to the positive and negative contacts on the base of the bulb for the circuit to work.
Well it can depend on how many bulbs it has etc, but generally it would be a series circuit.
There will be no change, because it is a parallel circuit.
In a parallel circuit nothing would happen. All the other light bulbs would remain on since there is an alternative path for current to flow. In a series circuit the entire circuit would be de-energized and all the bulbs would go out.
That would be a parallel circuit.
it would be ok in a circuit which didn't need a light bulb.
It depends on the circuit. If it is a constant-current circuit, any light bulbs connected in parallel with it will become brighter. If it is a constant-voltage circuit like a typical household circuit, nothing will happen. Any connected in series with it will go out.
The question is ambiguous, however one possibility is a parallel circuit, which would permit one light bulb to remain lit while the other light bulb was switched off. By contrast, if the light bulbs were connected in a series circuit, switching one light bulb off would cause both lights to go off.
That would be a parallel circuit.
That would be a parallel circuit.
Nothing much will happen except the same bulb will not blow..
No. In a parallel circuit, the resistance gets cut in half, so logically the bulbs would do the opposite and get brighter.
A parallel circuit
the circuit would not be complete. the lightbulb would not light or the buzzer would not buzz