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It would be possible but very unlikely. According to MLB Rule 10.09(a): "Score a sacrifice bunt when, before two are out, the batter advances one or more runners with a bunt and is put out at first base, or would have been put out except for a fielding error." MLB Rule 10.09(b) states: "Score a sacrifice bunt when, before two are out, the fielders handle a bunted ball without error in an unsuccessful attempt to put out a preceding runner advancing one base.". It would be very difficult to sacrifice with the bases loaded since when the defense sees the batter turn around to bunt their first thought would be to field the bunt and throw home to get the lead runner on a force out. Home would be the closest base to the fielder that fields the bunt so that would be the first base they would throw to. That would make a sacrifice bunt very difficult. However, if the fielder threw home and the runner from third beat the throw (maybe the runner was running with the pitch) and was called safe, the batter could be credited with a sacrifice per rule 10.09(b) above. This type of play, where the batter attempts a bunt when the runner from third base takes off for home when the pitch is delivered, is called a 'suicide squeeze'. Or, if the fielder made a poor throw and the runner was called safe at home, the batter could be credited with a sacrifice per rule 10.09(a) above. The 'suicide squeeze' play is something you might see a few times per season. It got its name from the fact that if the bunter misses the ball, or maybe the defense senses the play and calls for a pitchout, the runner coming home from third is going to be easily tagged out by the catcher.

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Q: Is it possible for a batter to get a sacrifice bunt if the bases are loaded If so How?
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