nope. OH is hydroxide which is insoluble except with a few things including potassium (K). so KOH is soluble, or aqueous.
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
Gel, aerosols, foam, emulsions, sols, solid foam, solid sols, solid aerosol
K+ and OH- is KOH -----------
MgSO4 + KOH --> MgOH + K2SO4 And I want to think that MgOH is a solid
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
Gel, aerosols, foam, emulsions, sols, solid foam, solid sols, solid aerosol
K+ and OH- is KOH -----------
Moles KOH = Molarity x Volume = 0.214 moles/liter x 0.0602 liters = 0.0129 moles KOH. Remember, 60.2 mL = 0.062L
MgSO4 + KOH --> MgOH + K2SO4 And I want to think that MgOH is a solid
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
If the KOH is in a moderately concentrated aqueous solution, the net reaction can be: 2 Al + 6 H2O => 2 Al(OH)3 + 3 H2. In this instance, the KOH does not undergo any net reaction; instead it catalyzes the reaction between aluminum and water by preventing the solid aluminum from maintaining a passivation layer on its surface. If the KOH is in a still more concentrated aqueous solution, the reaction can be: 2 Al + 4 KOH => K2Al2O4 + H2.
Koh Samui is in Thailand
KOH is potassium hydroxide.
KOH is Potassium Hydroxide.
KOH is potassium hydroxide.
KOH is a strong electrolyte