0
The expression for acceleration due to gravity is
ge=GMe/r2Acceleration due to gravity is inversely proportional to the square of the distance between the center of the Earth and the object. The acceleration due to gravity produced in an object on the surface of the Earth is dependent on the radius of the Earth. Earth is not a perfect sphere (slightly bulging out at the equator) its radius decreases as we move from the equator to the poles. At the equator and at sea level its value is about 9.78 m/s2 and at the poles it is 9.83 m/s2. Its mean value is taken as 9.8 m/s2 for all calculations.
Wiki User
∙ 12y ago
Wiki User
∙ 12y agoThe earth is not a perfect sphere: it's bulged in the centre. The lesser the distance between the centre of the earth and the surface, greater is the acceleration due to ravity and vice versa. The 'g' value is greater at the poles as it is nearer to the centre and comparitively lesser at the equator as it is farther away from the centre.
Wiki User
∙ 12y agoSince the Earth is an oblate spheroid and acceleration due to gravity is based on the distance to the centers of the mass of the two objects, acceleration due to gravity is stronger at the poles because the distance is shorter. However, the difference between equatorial gravity and polar gravity is not that different.
Polar Gravity: Approx: 9.8628 ms^-2
Equatorial Gravity: Approx: 9.7996 ms^-2
Usually 9.8 ms^-2 is used for acceleration due to gravity in general.
Wiki User
∙ 11y agoSince the Earth has a magnetic field, like all magnets, it has two poles. The North pole and the South pole. They represent the "ends" -- if you will -- of the magnetic field. The Equator is simply the halfway mark between the two, and the widest part of the Earth.
Wiki User
∙ 12y agoEarth is not a complete sphere. it bulges at the equator,so the distance between the center of th Earth and equator is more,so value of g is more at poles and less at equator.
Wiki User
∙ 11y agoValues of g at equator is lesss as compared to that of poles
Wiki User
∙ 10y agoBecause the Earth is slightly oblate, and in doing so along the surface,
you also move slightly farther from the planet's center of gravity.
Add your answer:
Earn +20 pts
Is the maximum value g at equator?
it is maximum at the poles
Why the motion of simple pendulum is slow at equator?
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
Why does the weight of a substance changes when weighed in a diff parts of world?
it is because earth is not perfectly spherical and also it spins on its Axis. The centrifugal force is greater at the equator and zero on poles. So the apparent weight at equators is lee because of centrifugal force. Also Earth is flattened at the poles which means that there is more acceleration due to gravity at poles[since g=GM/(R^2] In all, ate value of g ranges from around 9.7-9.9 on earth. This causes all the difference.
Why does the weight of an object change when it is moved from the equator to poles?
say mass(m) = 100 kgvelocity(v) at equator = 464.6 metres / secondradius(r) to earth surface = 6 371 000 metresacceleration due to gravity (g) = 9.82 (m / s) / s.the force of attraction (f) anywhere on earths surface, = m * g = 100 * 9.82 = 982 newtons.the force of repulsion / centripetal force (f) at the equator = mass * (v^2) / r =3.39 newtons
Why is gravity stronger at the poles?
You are closer to the center of the earth at the poles, r is smaller in g=GM/r2
Is there any difference between the value of g at the equator and the poles?
it is greater at poles than equator
Is the maximum value g at equator?
it is maximum at the poles
What is the value of g being used as a constant and why is this value used?
The value of g depends on latitude because the Earth is wider at the equator than at the poles. g = 9.80612 - 0.025865 cos (2 x latitude) metres/sec/sec It expresses how quickly an object accelerates after being dropped. The formula gives 9.7802 at the equator and 9.8320 at the poles. The weight of a 1 kg mass is g Newtons.
Is there gravity at the equator?
we know g equalls GM/R*R. Therefore g is inversly proportional to R spuare. Where R is radius of the planet. The R at the equator is the greatest. Hence the value of g is min at the equator. The value if g increases from the equator to the poles.
How does the acceleration of gravity depend on it's distance from the center of the Earth?
acceleration due to gravity is given by, g=GM/R2 Hence distance from the earth increases g decreases and viceversa. So g at poles is greater than g at equator.
Where is maximum value of g?
at the poles
Why the motion of simple pendulum is slow at equator?
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
What is the value of g at the poles of the earth?
g the acceleration due to gravity is 9.832 metres per second2 at the poles.
Why does the weight of a substance changes when weighed in a diff parts of world?
it is because earth is not perfectly spherical and also it spins on its Axis. The centrifugal force is greater at the equator and zero on poles. So the apparent weight at equators is lee because of centrifugal force. Also Earth is flattened at the poles which means that there is more acceleration due to gravity at poles[since g=GM/(R^2] In all, ate value of g ranges from around 9.7-9.9 on earth. This causes all the difference.
Why does the weight of an object change when it is moved from the equator to poles?
say mass(m) = 100 kgvelocity(v) at equator = 464.6 metres / secondradius(r) to earth surface = 6 371 000 metresacceleration due to gravity (g) = 9.82 (m / s) / s.the force of attraction (f) anywhere on earths surface, = m * g = 100 * 9.82 = 982 newtons.the force of repulsion / centripetal force (f) at the equator = mass * (v^2) / r =3.39 newtons
Which planet exerts the greatest pull of gravity?
Gravity is strongest at the poles of the earth because at the equator, the earth bulges out slightly. That puts objects at the equator "a bit farther away" from the earth, so they will be "pulled on less" owing to the fact that they are not as close.Gravity is influenced by the distance from the center of gravity and the mass of the object. The closer you are to the center of the earth, the greater the gravitational pull will be (and vice-versa).
What is the acceleration due to gravity at 49 degrees north latitude?
The acceleration due to gravity is not a constant across the face of the earth, as is astutely suggested from the nature of the question. The acceleration due to gravity on earth is given by g , and it is about 9.789 m/sec2 at the equator and about 9.823 m/sec2 at the poles. The observer might conclude with a bit of thought that the effect of gravity at the poles is a bit higher because of the shape of the earth, which is sometimes termed an oblate spheroid by astrophysicists. The earth is flattened up top and down bottom, and is a bit "fatter" in the middle. That means that a body on the equator is farther from the effective center of pull of gravity of earth. It will weigh less on the equator. And more on the poles where gravity is higher. At 49 degrees north latitude, the value of g is some 9.8707 m/sec2 there. Note that the general value often given for g is some 9.8 m/sec2, and it is applied for much work in "regular" mechanics.
