Max. memory address space= 216 X 2 bytes = 128 Kbytes
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
microprocessor can access 2^8 points which is 256 then we have 8 bit memory = 1 bytes then 1*256 =256 bytes
256 TB though strictly the limit is imposed by using 32 bits to address the clusters not the actual 32-bit processor
32 bit processor can access 4294967296 bit memory adderss.
The 8086/8088 can address a maximum of 220, or 1,048,576, or 1 MB of memory.
controller performs its operations faster than processor because controller has memory in it so it takes less time cycles for fetching of address or data from memory where as in processor memory is connected externally so time taken will be more to perform its operations.
Yes, because you are connected directly to ISP it will take no time to trace you back.
Because the processor is a 16 bit processor, and 64k is what you can address with a 16 bit processor.
On compatible computers a program cannot run directly from the hard disk drive without loading it into the memory because the processor can access and address only the main memory.
IP cameras - this camera is a computer processor, web server and a camera. This combination of technologies makes it possible to record images, compress them and transmit it in IP network or the Internet. Each camera has its own IP address and is connected directly to LAN or Internet - works completely independent. View IP Camera from t.co/1tqbO25qLV
Generally speaking, routers will unicast-forward incoming packets which have a network broadcast address as destination, unless they are directly connected to that network/subnet and therefore know that the destination address is a broadcast address